如何在单个链表中合并多个国家/地区 - 城市？

如何解决如何在单个链表中合并多个国家/地区 - 城市？

我试图将所有城市按国家/地区 UA、BE 等的顺序合并到一个链表中，但我只得到每个国家/地区城市的单独列表。我使用 itertools 做了以下方法

def crawl(self):
    cities = ('AU','BE','CA','CH','CN','CZ','DE','ES','FR','GB','IE','IT','JP','KR','MX','NL','NZ','PL','RO','RU','SE','SG','US')
    self.cities = dict()
    for city in cities:
        city_path = os.path.join(self.SITE_ROOT,'cities',city)

        with open(city_path,'r') as file:
            self.cities[city] = file.read().splitlines()

        c = list(itertools.chain.from_iterable(zip(self.cities[city]))) # better.
        print(c)

电流输出：

['Moscow','St. Petersburg','Sochi','Nizhny Novgorod','Yekaterinburg','Krasnodar','Tyumen']
['sweden','Stockholm','Malmø','Gothenburg','Göteborg','Uppsala','Solna']
['Singapore','Kallang']
['Los Angeles,CA','San Jose,'San Diego,'San Francisco,'Austin,TX','Dallas,'Arlington,VA','Washington,DC','Boston,MA','New York,NY','Chicago,IL','Minneapolis,MN','Denver,CO','Salt Lake City,UT']

预期输出（单个列表中的所有城市）：

['Moscow','Tyumen','sweden','Solna','Singapore','Kallang','Los Angeles,UT']

解决方法

只需在开始循环之前将 c 创建为空列表，并将每个国家/地区的单独列表添加到其中 - 您在循环中获得的城市：

def crawl(self):
    cities = ('AU','BE','CA','CH','CN','CZ','DE','ES','FR','GB','IE','IT','JP','KR','MX','NL','NZ','PL','RO','RU','SE','SG','US')
    self.cities = dict()
    c = []
    for city in cities:
        city_path = os.path.join(self.SITE_ROOT,'cities',city)

        with open(city_path,'r') as file:
            self.cities[city] = file.read().splitlines()

        c += list(itertools.chain.from_iterable(zip(self.cities[city]))) # better.
    print(c)