基于类的视图与其模型之间的源代码关系

如何解决基于类的视图与其模型之间的源代码关系

根据Django official URL，

models.py

from django.db import models
    class Publisher(models.Model):
        name = models.CharField(max_length=30)
        address = models.CharField(max_length=50)
        city = models.CharField(max_length=60)
        state_province = models.CharField(max_length=30)
        ...

views.py

from django.views.generic import ListView
from books.models import Publisher

class PublisherList(ListView):
    model = Publisher

urls.py

from django.urls import path
from books.views import PublisherList

urlpatterns = [
    path('publishers/',PublisherList.as_view()),]

在模板中，一个名为 object_list 的变量包含所有发布者对象。

{% extends "base.html" %}

{% block content %}
    <h2>Publishers</h2>
    <ul>
        {% for publisher in object_list %}
            <li>{{ publisher.name }}</li>
        {% endfor %}
    </ul>
{% endblock %}

我一直在深入研究 django 的源代码，以找出 Django 将 Publisher 模型的所有对象明确放入模板上下文 (object_list) 的确切位置。但到目前为止没有运气，有人可以分享一些见解吗？

解决方法

ListView 是 BaseListView 的子类。 object_list 属性已初始化 here:

class BaseListView(MultipleObjectMixin,View):
    """A base view for displaying a list of objects."""
    def get(self,request,*args,**kwargs):
        self.object_list = self.get_queryset()  # <--
        ...

.get_queryset() 方法的默认实现是 defined in MultipleObjectMixin：

def get_queryset(self):
    """
    Return the list of items for this view.
    The return value must be an iterable and may be an instance of
    `QuerySet` in which case `QuerySet` specific behavior will be enabled.
    """
    ...