JavaScript 中缩减数组的返回索引

如何解决JavaScript 中缩减数组的返回索引

我有这个有效负载，我试图在 JavaScript 中执行一些函数：

{
  "markets": [
    {
      "mtId": 27,"id": 1,"cId": "27-1","mt": "OVER_UNDER","selections": [
        {
          "id": 1,"price": 1.0896773820446435,"selectionStatus": 1,"name": "Over 0.5"
        },{
          "id": 2,"price": 12.159031085167172,"name": "Under 0.5"
        }
      ],"marketName": "Over Under 0.5"
    },{
      "mtId": 27,"id": 2,"cId": "27-2","price": 1.4531444546407393,"name": "Over 1.5"
        },"price": 3.207355058969988,"name": "Under 1.5"
        }
      ],"marketName": "Over Under 1.5"
    },"id": 3,"cId": "27-3","price": 2.3859593325595307,"name": "Over 2.5"
        },"price": 1.721681322609395,"name": "Under 2.5"
        }
      ],"marketName": "Over Under 2.5"
    }
  ]
}

基本上，我想获取市场数组，映射选择和

1. 返回价格与 0.5 之间存在差异的数组。
2. 然后我想获取该数组并返回最接近零的值。

我可以从这个函数中得到结果：

export const generateNumberClosestToZero = (markets) => {
  let goal = 0;

  let result = markets
    .map((market) =>
      market.selections.reduce(function (bookPercentage,selection) {
        return 0.5 - 1 / selection.price;
      },0)
    )
    .reduce(function (prev,current) {
      return Math.abs(current - goal) < Math.abs(prev - goal) ? current : prev;
    });
  return result;
};

但我还想做的是检索该减少值的索引，以便我可以在该特定市场上执行操作（例如 markets[1] 等）。有没有办法用我的代码来做到这一点，或者比我目前拥有的更好的解决方案？

解决方法

您可以将索引与值一起映射，并仅按值减少。

const
    generateNumberClosestToZero = (markets) => {
        let goal = 0;
        return markets
            .map((market,index) => [
                market.selections.reduce((bookPercentage,selection) => 0.5 - 1 / selection.price,0),index
            ])
            .reduce((a,b) => Math.abs(b[0] - goal) < Math.abs(a[0] - goal) ? b : a);
    },data = { markets: [{ mtId: 27,id: 1,cId: "27-1",mt: "OVER_UNDER",selections: [{ id: 1,price: 1.0896773820446435,selectionStatus: 1,name: "Over 0.5" },{ id: 2,price: 12.159031085167172,name: "Under 0.5" }],marketName: "Over Under 0.5" },{ mtId: 27,id: 2,cId: "27-2",price: 1.4531444546407393,name: "Over 1.5" },price: 3.207355058969988,name: "Under 1.5" }],marketName: "Over Under 1.5" },id: 3,cId: "27-3",price: 2.3859593325595307,name: "Over 2.5" },price: 1.721681322609395,name: "Under 2.5" }],marketName: "Over Under 2.5" }] };

console.log(generateNumberClosestToZero(data.markets));

,

我认为这就是您要找的。​​p>

const markets = [{"mtId": 27,"id": 1,"cId": "27-1","mt": "OVER_UNDER","selections": [{"id": 1,"price": 1.0896773820446435,"selectionStatus": 1,"name": "Over 0.5"},{"id": 2,"price": 12.159031085167172,"name": "Under 0.5"}],"marketName": "Over Under 0.5"},{"mtId": 27,"id": 2,"cId": "27-2","price": 1.4531444546407393,"name": "Over 1.5"},"price": 3.207355058969988,"name": "Under 1.5"}],"marketName": "Over Under 1.5"},"id": 3,"cId": "27-3","price": 2.3859593325595307,"name": "Over 2.5"},"price": 1.721681322609395,"name": "Under 2.5"}],"marketName": "Over Under 2.5"}];

const generateNumberClosestToZero = (markets) => {
  let closest = 9999; // closest value found so far
  let index = []; // output
  markets.forEach((m,n) => {
    m.selections.forEach((s,t) => {
      if (s.price < closest) { // if closer value found
        closest = s.price; // set closest value to new value
        index[0] = n; // store market index
        index[1] = t; // store selections index
      }
    })
  });
  return index;
};

const closest = generateNumberClosestToZero(markets);

console.log(closest); // get indexes
console.log(markets[closest[0]].selections[closest[1]]); // access results from market

输出：

[
  0,0
]
{
  "id": 1,"name": "Over 0.5"
}