Python：在装饰函数内改变装饰器内置的对象并返回它

如何解决Python：在装饰函数内改变装饰器内置的对象并返回它

我想要一个装饰器 build_and_fetch_response 来构建响应并环绕准会话管理器 managed_exception，后者又环绕实际的业务逻辑功能 fetch：

from datetime import datetime


def build_and_fetch_response(managed_exception):
    def wrapper(*args,**kwargs):
        response = {'errors': []}
        managed_exception(response)
        return response    
    return wrapper


@build_and_fetch_response
def managed_exception(response):
    def outter_wrapper(fetch):
        def inner_wrapper(*args,**kwrags):
            dt = datetime.utcNow()
            try:
                fetch(dt)
            except Exception as e:
                response['errors'].append(e)
        return inner_wrapper
    return outter_wrapper


@managed_exception
def fetch(dt):
    print(f'fetching resource,time is: {dt}')
    assert True == False

这产生了相当预期的结果：

>>> fetch
{'errors': []}

>>> fetch()
Traceback (most recent call last):
  File "<input>",line 1,in <module>
    fetch()
TypeError: 'dict' object is not callable

我想将响应对象、会话管理器和逻辑的构建分开，所以这是不行的：

# what I don't want to do:
def build_and_fetch_response(managed_exception):
    def wrapper(*args,**kwargs):
        # response is built somewhere inside
        response = managed_exception()
        return response    
    return wrapper

问题：

如何实现返回一个可变对象，该对象构建在最顶层的装饰器中并作为参数传递给较低的装饰函数？