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Avro.avroexception:genericrecord 需要针对记录模式写入,但找到了 avro.generic.genericrecord

如何解决Avro.avroexception:genericrecord 需要针对记录模式写入,但找到了 avro.generic.genericrecord

我从融合的卡夫卡制作人那里得到了例外

Avro.AvroException: GenericRecord 需要针对记录架构写入但找到 Avro.Generic.GenericRecord \n 在 Avro.Generic.DefaultWriter.EnsureRecordobject(RecordSchema s,Object value) \n 在 Avro.Generic.DefaultWriter.WriteRecord(RecordSchema 架构,对象值,编码器编码器) \n 在 Avro.Generic.DefaultWriter.Write(Schema schema,Object value,Encoder encoder) \n 在 Avro.Generic.DefaultWriter.WriteArray(ArraySchema schema,Encoder encoder) \n 在 Avro.Generic.DefaultWriter.Write(Schema schema,Encoder encoder) \n 在 Avro.Generic.DefaultWriter.WriteRecord(RecordSchema schema,Encoder encoder)

Schema:
var s = (RecordSchema)RecordSchema.Parse(
                @{
  "name": "StaticDatanotification","type": "record","namespace": "KafkaName","fields": [
    {
      "name": "UniqueID","type": "string"
    },{     
      "name": "DataList","type": {
        "type": "array","items":{
        "name": "DataList_record","type":"record","fields": [
            {
              "name": "FieldName","type": "string"
            },{
              "name": "OldValue","type": "string"
            }
          ]
        }
      }
    }
  ]
}

var child = (RecordSchema)RecordSchema.Parse(
                @{
        "name": "DataList_record","type": "string"
            }
          ]
        }

C# 代码

var recordStaticData = new GenericRecord(s);
recordStaticData.Add("UniqueID","123456");

List<GenericRecord> genericRecords = new List<GenericRecord>();
for (int i = 0; i < 3; i++)
{
GenericRecord StaticList = new GenericRecord(child);
StaticList.Add("FieldName","Name");
StaticList.Add("OldValue",i.ToString());
genericRecords.Add(StaticList);
}
recordStaticData.Add("DataList",genericRecords.ToArray());

var dr = producer.ProduceAsync("Topic",new Message<string,GenericRecord>{ Key = System.Guid.NewGuid().ToString("N"),Value = recordStaticData });

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