如何使用 array.filter 方法过滤单词

如何解决如何使用 array.filter 方法过滤单词

我只想知道如何使用 filter 方法返回 name 属性等于“Bob”的对象的索引。 （在这种情况下，为简单起见，只有一个索引）

data.json

[
 {
    "index": "14","name": "Bob","age": "23",},{
    "index": "23","name": "John","age": "30",{
    "index": "17","age": "25",]

app.js

const data = require("./data.json");


const searchword = "Bob";
const result = data.filter((word) => ???word === searchword???);
console.log(result);

应该显示索引：14,17

解决方法

这就像一个 filter 和一个 map

const data = [
 {
    "index": "14","name": "Bob","age": "23",},{
    "index": "23","name": "John","age": "30",{
    "index": "17","age": "25",]

const searchWord = "Bob";
const result = data.filter(x => x.name == searchWord) // find by searchWord
                   .map(x => x.index); // get the index
console.log(result.join(",")); // result is an array

,

使用 reduce 方法

const data = [
  {
    index: "14",name: "Bob",age: "23",{
    index: "23",name: "John",age: "30",{
    index: "17",age: "25",];

const getIndexes = (arr,word) =>
  arr.reduce(
    (acc,{ index,name }) => (name === word ? acc.concat(index) : acc),[]
  ).toString();

console.log(getIndexes(data,"Bob"));