在python中打印螺旋矩阵

如何解决在python中打印螺旋矩阵

在 Python 中卡在打印螺旋矩阵图案的内部正方形

代码

num=int(input("enter numbers:")) # taking value num=4
arr=[[0 for x in range(num)] for y in range(num)]
n=1
low=0
high=num-1
c=1
# c=int((num+1)/2)
for i in range(c):
    for j in range(low,high+1): #left to right
        arr[i][j]=n
        n=n+1
    for j in range(low+1,high+1):# top to bootom
        arr[j][high]=n
        n=n+1
    for j in range(high-1,low-1,-1): # right to left
        arr[high][j]=n
        n=n+1
    for j in range(high-1,low,-1): # down to up
        arr[j][low]=n
        n=n+1
    for j in range(low+1,high): # inner left to right
        arr[low+1][j]=n
        n=n+1
    # for j in range(1,high):
    #     arr[j][high]=n
    #     n=n+1
    # for j in range(1):
    #     arr[low+1][j]=n
    #     n=n+1

for i in range(num):
    for j in range(num):
        print(arr[i][j],end="\t")
    print()

预期输出

1 2 3 4

12 13 14 5

11 16 15 6

10 9 8 7

我的输出

1 2 3 4

12 13 14 5

11 0 0 6

10 9 8 7

解决方法

我改编了你的程序。它有一个很好的推理，唯一的问题是您手动编写循环。相反，当四个拳头循环编写数字绘制正方形时，我只是编写了一个程序来多次应用这些循环。

num=int(input("enter numbers:")) # taking value num=4
arr=[[0 for x in range(num)] for y in range(num)]
n=1
# c=int((num+1)/2)

def square(low,high,array):
    global n
    for j in range(low,high+1): #left to right
        array[i][j]=n
        n=n+1
    for j in range(low+1,high+1):# top to bootom
        array[j][high]=n
        n=n+1
    for j in range(high-1,low-1,-1): # right to left
        array[high][j]=n
        n=n+1
    for j in range(high-1,low,-1): # down to up
        array[j][low]=n
        n=n+1

if num%2==0:
  rg=num//2
else:
  rg=(num+1)//2
for i in range(rg):
    square(i,num-1-i,arr)

rg 只是奇数执行正确的次数。