SQL：表列的缺失百分比和唯一计数

如何解决SQL：表列的缺失百分比和唯一计数

假设我有一个有 4 列的表格。 我想知道的每一列：

• 缺失值的百分比（空计数）和
• 独特的计数

如果我有一个包含 A B C 和 D 列的表格， 例如，上述情况的预期结果是：

Column_Name | PctMissing | UniqueCount
A           | 0.15       | 16
B           | 0          | 320
C           | 0.3        | 190
D           | 0.05       | 8

解决方法

如果您知道列数，我可能只会使用 union all：

select 'a' as Column_Name,1.0*count(case when a is null then 1 end)/count(*) as PctMissing,count(distinct a) as UniqueCount
from t
union all
select 'b' as Column_Name,1.0*count(case when b is null then 1 end)/count(*) as PctMissing,count(distinct b) as UniqueCount
from t
union all
select 'c' as Column_Name,1.0*count(case when c is null then 1 end)/count(*) as PctMissing,count(distinct c) as UniqueCount
from t
union all
select 'd' as Column_Name,1.0*count(case when d is null then 1 end)/count(*) as PctMissing,count(distinct d) as UniqueCount
from t

Fiddle Demo

根据您的数据库，还有其他方法，但可能比 union all 更容易混淆。

,

我会这样写：

select 'a' as column_name,avg(case when a is null then 1.0 else 0 end) as missing_ratio,count(distinct a) as unique_count
from t
union all
select 'b' as column_name,avg(case when b is null then 1.0 else 0 end) as missing_ratio,count(distinct b) as unique_count
from t
union all
select 'c' as column_name,avg(case when c is null then 1.0 else 0 end) as missing_ratio,count(distinct c) as unique_count
from t
union all
select 'd' as column_name,avg(case when d is null then 1.0 else 0 end) as missing_ratio,count(distinct d) as unique_count
from t;