微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

Python:scipy.sparse / pandas 稀疏矩阵中的空值被转换为大的负整数

如何解决Python:scipy.sparse / pandas 稀疏矩阵中的空值被转换为大的负整数

我正在尝试使用 scipy 稀疏 COO 矩阵,但我遇到了奇怪的错误,空值被转换为大的负整数。这是我在做什么:

import pickle5 as pk5
from scipy import sparse
import pandas as pd

with open('some_file.pickle','rb') as f:
    df = pk5.load(f)

原始稀疏 df 看起来是正确的:

df.iloc[0:5,0:4])

 1028799.3_nuc_coding  1156994.3_nuc_coding  1156995.3_nuc_coding
0                   1.0                   NaN                   NaN
1                   NaN                   1.0                   NaN
2                   NaN                   NaN                   NaN
3                   NaN                   NaN                   NaN
4                   NaN                   NaN                   NaN

运行 dropna 工作正常,所以它实际上是空值。

df.iloc[0].dropna().index[:3]

Index(['1028799.3_nuc_coding','1280.11650_nuc_coding','1280.11655_nuc_coding'],dtype='object')

但是对其执行任何操作都会将 NaN 值更改为 -9223372036854775808。例如这里是df.T

                                      0                    1  \
1028799.3_nuc_coding                    1 -9223372036854775808   
1156994.3_nuc_coding -9223372036854775808                    1   
1156995.3_nuc_coding -9223372036854775808 -9223372036854775808   

                                        2                    3  \
1028799.3_nuc_coding -9223372036854775808 -9223372036854775808   
1156994.3_nuc_coding -9223372036854775808 -9223372036854775808   
1156995.3_nuc_coding -9223372036854775808 -9223372036854775808   

                                        4  
1028799.3_nuc_coding -9223372036854775808  
1156994.3_nuc_coding -9223372036854775808  
1156995.3_nuc_coding -9223372036854775808  

我在 df.iterrows() 和使用上面的代码在 scipy 中转换到 coo 矩阵时遇到了类似的错误

coo_mat = sparse.coo_matrix(df.values,shape=df.shape)
print(coo_mat)
(0,0)  1
  (0,1)    -9223372036854775808
  (0,2)    -9223372036854775808
  (0,3)    -9223372036854775808
  (0,4)    -9223372036854775808
  (0,5)    -9223372036854775808
  (0,6)    -9223372036854775808
  (0,7)    -9223372036854775808
  (0,8)    -9223372036854775808
  (0,9)    -9223372036854775808
  (0,10)   -9223372036854775808
  (0,11)   -9223372036854775808
  (0,12)   -9223372036854775808
  (0,13)   -9223372036854775808
  (0,14)   -9223372036854775808
  (0,15)   -9223372036854775808
  (0,16)   -9223372036854775808
  (0,17)   -9223372036854775808
  (0,18)   -9223372036854775808
  (0,19)   -9223372036854775808
  (0,20)   -9223372036854775808
  (0,21)   -9223372036854775808
  (0,22)   -9223372036854775808
  (0,23)   -9223372036854775808
  (0,24)   -9223372036854775808
  : :

解决方法

感谢@hpaulj 的提示!问题是我的 dtype 是一个 int。因此,将其重铸为 float 可以解决问题。示例:

df.iloc[0:5,0:4].astype(float).T

                          0   1   2    3  4
1028799.3_nuc_coding    1.0 NaN NaN NaN NaN
1156994.3_nuc_coding    NaN 1.0 NaN NaN NaN
1156995.3_nuc_coding    NaN NaN NaN NaN NaN
1156996.3_nuc_coding    NaN NaN NaN NaN NaN

类似地,一旦类型更改为浮点数,其他操作(如 iterrows 和强制转换为 coo_matrix)也能按预期工作。

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。