需要将文本文件中的每 12 个整数除以 12 以模拟一年中的几个月

如何解决需要将文本文件中的每 12 个整数除以 12 以模拟一年中的几个月

我正在创建一个程序，将文本文件中的每 12 个整数除以模拟获取一年的平均降雨量，举个例子，如果在单独的行中有 15 个整数，它将取第一个12 并将总数除以 12 以获得该年的平均值，然后它将最后三个分开并使其成为新的一年，我正在考虑制作一个将月份计数器重置为 0 的 else 语句，但我可以使用一些建议。

def main():
    rain_per_month = open('RainperMonth.txt','r')
#this is to open the text file with the numbers

    months = 0
#start the accumulator to keep track of the total amount of months
    rainfall = 0
#this is to keep track of the total amount of rainfall
    years = 0
    for line in rain_per_month:
#this is a loop that will go line by line and begin to modify the variables
        months += 1
#this is increasing the number of months according to the number of lines
#for example if there are 15 lines it will keep count of those 15 lines as seperate months
        rainfall = int(line) + rainfall
#this will convert the numbers on the line from being a symbol for 4 to really being the number 4 and 
adding it to the total amount of rainfall
    if months % 12 == 0:
        avg_rain = rainfall / months
        
#Where I am going to seperate the different months and calculate the total for eac
    
    print(avg_rain)
#where the caculations for the rain will be made
main()

解决方法

只是稍微修改了您的逻辑。 步骤 ->

1. 将文件内容加载到列表中。
2. 取长度为 12 的列表的子集（参见 for 循环中的步数）
3. 计算平均值。
4. 这里，enumerate 将自动递增年份。

def main():
    with open('RainperMonth.txt','r') as f:
        content = f.read().splitlines()
    for years,i in enumerate(range(0,len(content),12),start=1):
        rain_per_month = content[i:i+12]
        # print(rain_per_month)
        rainfall = 0
        for months,line in enumerate(rain_per_month,start=1):
            rainfall = int(line) + rainfall
        avg_rain = rainfall / len(rain_per_month)
        print(f'avg_rain = {avg_rain} for year = {years}')

main()