从两个表sqlite中选择数据并将其返回到JSON

如何解决从两个表sqlite中选择数据并将其返回到JSON

我有两张桌子：

IdUser	名字	姓氏
1	name1	last1
2	name2	last2

2 - 书籍

IdBook	NameBook	IdUser
1	book1	1
2	book2	1
3	book3	2

我正在使用 React-Native 和 react-native-sqlite-storage

listofBooks() {
    return new Promise(resolve => {
      var books= [];    
      this.initDB()
        .then(db => {
          db.transaction(tx => {
            tx.executesql('SELECT * from Users INNER JOIN Books ON Users.IdUser= Books.IsUser',).then(([tx,results]) => {
              var len = results.rows.length;
              if (len > 0) {
                for (let i = 0; i < len; i++) {
                  let row = results.rows.item(i);
                  const { IdUser,FirstName,LastName,NameBook } = row;
                  books.push({ IdUser,NameBook  });
                }
                resolve(JSON.stringify(books));
              }
            });
          })
            .then(result => {
              this.closeDatabase(db);
            })
            .catch(err => {
              console.log(err);
            });
        })
        .catch(err => {
          console.log(err);
        });
    });
  }

函数返回这个json

[
  {
    "IdUser": 1,"FirstName": "name1","LastName": "last1","NameBook": "book1",},{
    "IdUser": 1,"NameBook": "book2",{
    "IdUser": 2,"FirstName": "name2","LastName": "last2","NameBook": "book3",}
]

但我希望我的 json 是这样的

[
  {
    "IdUser": 1,"NameBook": ["book1","book2"],}
]

是否有一个（react-native）库可以让我轻松解决这个问题？感谢帮助。