释放按钮时发出声音 类Button：脚本

如何解决释放按钮时发出声音 类Button：脚本

我已经被这个问题困扰了很长时间了。我有一个按钮类。您已经可以选择按钮，单击按钮，然后释放按钮（这会导致事件发生）。我想在你松开按钮时发出声音，但我不能。我不明白你应该怎么做，我已经尝试了一切。换句话说，我想确保鼠标在已经选择按钮时被按住，然后如果它在那个位置释放，一个名为 release 的属性将在一帧内切换为 True。然后我可以检查 release 是否为 True，然后我会播放声音。我的问题：我需要检查什么条件才能将 release 属性切换为 True 一帧？这是我的代码结构：

# "mouse_down" is a global for when the mouse is being held down
# "clicked" is a global variable for the first frame at which the mouse is held down
# I also have a "release" global variable for the frame that the mouse stops clicking,this variable isn't currently being used.

class Button:
    def __init__(self,pos,size,font,text,colors):
        """
        colors[n]
        
        0: fill   unselected
        1: border unselected
        2: text   unselected
        3: fill   selected
        4: border selected
        5: text   selected
        6: fill   clicked
        7: border clicked
        8: text 
        """

        self.pos = pos
        self.size = size
        self.font = font
        self.text = text
        self.colors = colors
        self.selected = False
        self.clicked = False
        self.release= False

    def update(self):
        # If the mouse is hovering on the button
        if (pygame.mouse.get_pos()[0] > button.pos[0] and pygame.mouse.get_pos()[0] < button.pos[0] + button.size[0]) and (pygame.mouse.get_pos()[1] > button.pos[1] and pygame.mouse.get_pos()[1] < button.pos[1] + button.size[1]):
            self.selected = True
            
            if clicked: 
                self.clicked = True

            if not mouse_down:
                self.clicked = False

        else:
            self.selected = False
            self.clicked = False

现在只是为了澄清，让我们假设我用鼠标按住单击按钮，将其拖到按钮的位置，然后松开，释放属性不应打开，因为鼠标需要放在按钮上才能开始。

解决方法

如果鼠标与按钮发生碰撞，最好使用 pygame.rect.collidepoint 而不是

if (pygame.mouse.get_pos()[0] > button.pos[0] and pygame.mouse.get_pos()[0] < button.pos[0] + button.size[0]) and (pygame.mouse.get_pos()[1] > button.pos[1] and pygame.mouse.get_pos()[1] < button.pos[1] + button.size[1]):

工作原理：

• 主循环：获取 MOUSEBUTTONUP 事件（释放鼠标按钮时发生）
• 将此事件发送到按钮
• 如果实际鼠标点击 (MOUSEBUTTONDOWN) 发生在按钮中，也发送
• 如果两个事件都为 True，则播放声音

在按钮类中：

• __init__：生成碰撞区域+文本Surface
• update：绘制矩形，然后将文本居中，然后检查是否碰撞 + 事件 + 按下按钮

类Button：

class Button:
    def __init__(self,pos,size,font,text,color):
        self.rect = Rect(pos,size) # 
        self.text = font.render(text,color) # text surface
        self.button_down_on = False

    def update(self,release_event):
        # draw the button
        pygame.draw.rect(screen,(100,100,100),self.rect)
        width,height = self.text.get_size()
        screen.blit(self.text,(int(self.rect.x + self.rect.width / 2 - width / 2),int(self.rect.y + self.rect.height / 2 - height / 2)))

        # check collisions
        if release_event and self.rect.collidepoint(pygame.mouse.get_pos()):
            if self.button_down_on: # if the mouse began to press on this button
                print('play sound')

脚本

import pygame
from pygame.locals import *

pygame.init()
screen = pygame.display.set_mode((640,480))

button = Button((10,10),(200,40),pygame.font.SysFont('consolas',20),'Test',(127,255,255))

running = True
while running:
    release_event = False
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            exit()
        elif event.type == MOUSEBUTTONDOWN:
            # check if the click begin on a button
            button.button_down_on = button.rect.collidepoint(event.pos)
        elif event.type == MOUSEBUTTONUP:
            release_event = True # send this event to Button.update

    screen.fill((255,255))
    button.update(release_event)
    pygame.display.flip()