如何解决如何按值减少对象数组
const array = [
{ someDate: "2021-01-19T14:18:20.000",count: 13},{ someDate: "2021-01-28T12:57:15.000",count: 12},count: 10},{ someDate: "2021-01-19T14:18:20.000",count: 9},{ someDate: "2021-02-07T10:32:37.000",count: 7},count: 5},count: 4}
];
如果日期相同,我想按日期减少对象并获得该日期的计数总和。这就是我想要达到的结果
const array = [
{ someDate: "2021-01-19T14:18:20.000",count: 26},count: 22},];
我怎样才能做到这一点?任何示例将不胜感激!
解决方法
这个想法是跟踪您通过 someDate
看到的那些,然后将该记录的计数相加。
const array = [
{ someDate: "2021-01-19T14:18:20.000",count: 13},{ someDate: "2021-01-28T12:57:15.000",count: 12},count: 10},{ someDate: "2021-01-19T14:18:20.000",count: 9},{ someDate: "2021-02-07T10:32:37.000",count: 7},count: 5},count: 4}
];
const result = array.reduce((acc,current) => {
const {someDate,count} = current;
const existing = acc.find(a => a.someDate === someDate);
if (existing) {
existing.count += count;
} else {
acc.push(current);
}
return acc;
},[]);
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