2D 网状网络 fipy 的质量平衡不正确

如何解决2D 网状网络 fipy 的质量平衡不正确

我希望表示 2D 网络中的扩散（扩散系数取决于 phi 的值）和特定单元格中的设定 phi 输入率（因此不是脸上的 BC）。这似乎是一个非常简单的场景，但是，我一定是做错了什么，因为我在计算这个例子时得到了非常奇怪的结果：

from fipy import *
from fipy.meshes.nonUniformGrid1D import NonUniformGrid1D as Grid1D
from fipy.meshes.nonUniformGrid2D import NonUniformGrid2D as Grid2D
from fipy.tools import numerix as np

ny = 6 
nx = 1 
dy = [0.2,0.2,0.2] 
dx = 0.2 
translate = [[0.0],[-1.2]]
meshes = Grid2D(ny = ny,nx = nx,dy = dy,dx = dx) + translate


nx = 2 
ny = 1 
dx = [0.05,0.05]
dy = 0.2 
translate = [[0.2],[-0.2]] 
mesh = Grid2D(ny = ny,dx = dx) + translate

meshes = meshes + mesh

nx = 2 
ny = 1 
dx = [0.05,[-0.6]] 
mesh = Grid2D(ny = ny,[-1.0]] 
mesh = Grid2D(ny = ny,dx = dx) + translate

meshes = meshes + mesh

ny = 3 
nx = 1 
dy = [0.2,0.2]
dx = 0.2 
mesh = Grid2D(ny = ny,dx = dx) 

meshes = meshes + mesh


ny = 1 
nx = 1 
dx = [1.]
dy = 0.2 
translate = [[0.2],[0.2]]
mesh = Grid2D(ny = ny,dx = dx) + translate

meshes = meshes + mesh
vol = meshes.cellVolumes
phi = CellVariable(mesh= meshes,value = 0.,hasOld = True)
Source = CellVariable(mesh= meshes,value = 0.)
Source.constrain(10.,where = abs(vol - 0.2) < 0.001) 
#addition of Source * dt to meshes at each step on the selected cell
dt = 1e-6#0.9*( min(meshes.cellVolumes) ** 2) / (2 *max(Source.faceValue ))

cumulatedIn = 0. # cumulated input
eq = (TransientTerm(var = phi) == DiffusionTerm(var = phi,coeff= phi.faceValue)+ Source )
steps = 3
for _ in range(steps):
   print('steps ',_,dt)
   res= 1e5
   loop =0 
   while (res > 1e-3* max(abs(Source.value)) or res > 1e-3* max(abs(phi.value)) )and loop < 1000:
           res =  eq.sweep(dt= dt)
           loop += 1
           print('res: ',res)
           print('maxRes: ',1e-3* max(abs(Source.value)),1e-3* max(abs(phi.value)) )
   cumulatedIn += sum(Source * dt * meshes.cellVolumes)
   phi.updateOld
   print('mass balance ',sum(phi * meshes.cellVolumes) - cumulatedIn,'\nphi content in mesh ',sum(phi * meshes.cellVolumes))
   print('phi matrix\n',phi)

phi 的含量保持不变而不是增加。 当我改用 solve 时，该值确实会增加。然而，因为扩散系数取决于 phi，我宁愿使用扫描。 有人能解释一下问题的根源吗？

2) 此外，扩散项应该代表浓度驱动的平流：J = [constante coeff to be added] * nabla_dot_(phi * nabla(phi))。 或者用 fipy 显式方程写成： (constante_coeff * phi * phi.faceGrad).发散。 我当前的扩散术语是表示这一点的正确方式吗？

感谢您的帮助！

解决方法

.updateOld() 是一个方法，而不是一个属性（它需要括号）。