过滤数组是否包含另一个数组的元素

如何解决过滤数组是否包含另一个数组的元素

我有两个数组，例如：

arr1 = ["orange","banana"]
arr2 = [{"fruit"= ["pineapple","banana"]},{"fruit"= ["grapes","apple"]},{"fruit"= ["apple","orange"]}]

我需要过滤第二个数组中是否存在第一个元素。

我正在尝试这样做：

let kFilter = arr1.map(itemY => { return itemY; }); 
let filteredK = arr2.filter(itemX => kFilter.includes(itemX.fruit));

但没有成功:-(

解决方法

//declaration variables correctly
let arr1 = ["orange","banana"]
let arr2 = [{"fruit" : ["pineapple","banana"]},{"fruit" : ["grapes","apple"]},{"fruit": ["apple","orange"]}];

//filter using reduce
arr2.filter((e)=>arr1.reduce((a,i)=>a||e["fruit"].includes(i),false))

//filter using some
arr2.filter((e)=>arr1.some((i)=>e["fruit"].includes(i)))

,

首先为了避免过多的迭代，将简单数组转换为如下所示的对象。否则复杂度会很高

const fruitMap = {
    "orange": 1,"banana": 1
};

然后你必须遍历第二个数组中的每个项目

arr2.forEach(fruitsObj => {
    let arr = fruitsObj['fruit'];
    for (let i = 0; i < arr.length(); i ++) {
        if (fruitMap[arr[i]]) {
             arr.splice(i,1);
        }
    }
})