matlibplot中两个向量之间的填充区域

如何解决matlibplot中两个向量之间的填充区域

以下代码计算以下向量： 方向 矢量 （红色） 和 两个矢量（蓝色），它们是通过将红色矢量旋转 60 度时钟 - 和逆时针方向而产生的。

import matplotlib.pyplot as plt
import numpy as np


def Visualize(orienVector,vector1,vector2):
 # Create figure and subplot
 fig = plt.figure()
 ax = fig.add_subplot(1,1,1)

 # Plot data points
 #ax.scatter(vector1[0],vector1[1],color='blue')
 #ax.scatter(vector2[0],vector2[1],color='orange')

 # Set limits for x and y axes
 plt.xlim(-1,1)
 plt.ylim(-1,1)

 # ===== Important bits start here =====

 # Set properties of spines
 ax.spines['top'].set_color('none')
 ax.spines['left'].set_position('zero')
 ax.spines['right'].set_color('none')
 ax.spines['bottom'].set_position('zero')

 # Set axis tick positions
 ax.xaxis.set_ticks_position('bottom')
 ax.yaxis.set_ticks_position('left')

 # Set specific tick locations
 ax.set_xticks([-10,-5,5,10])
 ax.set_yticks([-10,10])

 # ===== End Of Important Bits =====

 # Draw arrows
 ax.arrow(0,vector1[0][0],vector1[1][0],head_width=0.03,head_length=0.1,lw=1,fc='blue',ec='blue',length_includes_head=True)
    
 ax.arrow(0,vector2[0][0],vector2[1][0],length_includes_head=True)

 ax.arrow(0,orienVector[0][0],orienVector[1][0],lw=2,fc='red',ec='red',length_includes_head=True)

 plt.show()

# rotation matrix clockwise
def rotMatrixClockWise(angle):
 c,s = np.cos(angle),np.sin(angle)
 R = np.array([[c,-s],[s,c]])
 return R 

# rotation matrix clockwise
def rotMatrixCounterClockWise(angle):
 c,s],[-s,c]])
 return R  

# center of the poit of interests POIS
POI_X = [10,12,15,17,20,50]
POI_Y = [20,30,25,22,19,35]

# position of the pedestrian 
pedPostion = np.array([[3],[4]])

# range of the horisontal angel view
spanningAngle = np.radians(60)

# calculate the cone 
for angle in range(0,360,5):
 
    
 # calculating the component of orientation vector V0,where the length |V0| = 1 
 x0 = 5*np.cos(np.radians(angle))
 y0 = 5*np.sin(np.radians(angle)) 
 v0 = np.array([[x0],[y0]])
 
 v1 = rotMatrixCounterClockWise(spanningAngle).dot(v0) 
 v2 = rotMatrixClockWise(spanningAngle).dot(v0) 


 Visualize(v0,v1,v2)

这个向量的输出看起来像

我正在尝试填充蓝色矢量之间的区域以获得如下所示的锥体：

圆锥的头部 (0,0) 与圆弧之间的距离始终为 5

但是，我无法让它工作。我是 Matlibplot 的新手

解决方法

您可以通过分析找出圆弧中的点（圆的一部分，因此 y = +- (1-x^2)**0.5），将它们添加到由红色的原点和末端定义的多边形中和黄色向量，然后使用 https://matplotlib.org/stable/api/_as_gen/matplotlib.pyplot.fill.html。

填充多边形的示例如下：https://matplotlib.org/stable/gallery/lines_bars_and_markers/fill.html#sphx-glr-gallery-lines-bars-and-markers-fill-py

,

也许不完全是你要找的，但你可以在向量之间创建一个楔子。拟合椭圆并填充其间的坐标会更合适。这是楔形的示例。

import matplotlib.pyplot as plt,numpy as np
from matplotlib import patches
v1 = np.array((1,2))
v2 = np.array((1,-2))
base = np.array((0,0))
theta1 = np.rad2deg(np.arctan(v1[1] / v1[0]))
theta2 = np.rad2deg(np.arctan(v2[1] / v2[0]))

fig,ax = plt.subplots()

a,b = theta1,theta2 
if b > a:
   a,b = b,a
artist = patches.Arc(base,width = 1,height = 1,theta1 = a,theta2 = b,color = 'green')
ax.arrow(*base,*v1,color = 'black')
ax.arrow(*base,*v2,*(v2 + v1),color = 'red')
wedge = patches.Wedge(base,r = 1,theta1 = theta2,theta2 = theta1,color = 'green')
ax.add_patch(wedge)

fig.show()