javafx中codearea的自动补全

如何解决javafx中codearea的自动补全

在 javafx 中键入自动完成时，如何在 codearea 中的当前插入符号位置创建列表视图？到目前为止，我找到了当前正在键入的单词，并查看该单词是否包含在数组中。这是我到目前为止的代码。提前致谢！

String[] keyphrases = new String[]{"int main(){\n}","cout","cin"};

((CodeArea)tabPane.getSelectionModel().getSelectedItem().getContent()).textproperty().addListener(new changelistener<String>()
                        {
                            @Override
                            public void changed(ObservableValue<? extends String> observableValue,String s,String s2) {
                                CodeArea sto = ((CodeArea)tabPane.getSelectionModel().getSelectedItem().getContent());
                                String curr = "";
                                String currFinal = "";
                                for (int i = sto.getAnchor(); i > 0; i--) {
                                    if (sto.getText().charat(i) == '\n' || sto.getText().charat(i) == ' ') {
                                        break;
                                    }else {
                                        curr += sto.getText().charat(i);
                                    }
                                }
                                for (int i = curr.length()-1; i >= 0; i--) {
                                    currFinal += curr.charat(i);
                                }
                                System.out.println(currFinal);
                                ArrayList<String> fil = new ArrayList<String>();
                                for (int i = 0; i < keyphrases.length; i++) {
                                    if (keyphrases[i].contains(currFinal)) {
                                        fil.add(keyphrases[i]);
                                    }
                                }
                                //display fil as listview in caret position?
                            } 
                        });

解决方法

如果您询问如何在插入符号位置显示 ListView，请查看以下方法。这是在当前插入符号位置显示 ListView 的通用高级方法。您可以根据自己的要求关联逻辑和更改。

我相信这将为您提供有关如何接近的必要基础知识。话虽如此，还有许多其他更好的方法。

核心思想是依靠插入符节点（Path）的边界，而不是做复杂的计算来找到插入符在文本中的位置。

import javafx.application.Application;
import javafx.geometry.Bounds;
import javafx.geometry.Insets;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.ListView;
import javafx.scene.control.TextArea;
import javafx.scene.layout.Priority;
import javafx.scene.layout.Region;
import javafx.scene.layout.VBox;
import javafx.scene.shape.Path;
import javafx.stage.Popup;
import javafx.stage.Stage;

public class TextAreaCaretPositionDemo extends Application {
    private Bounds caretBoundsInScreen;
    private Node caret;

    @Override
    public void start(Stage stage) throws Exception {
        final VBox root = new VBox();
        root.setSpacing(10);
        root.setPadding(new Insets(10));
        final Scene sc = new Scene(root,350,200);
        stage.setScene(sc);
        stage.setTitle("TextArea Caret Position");
        stage.show();

        TextArea textArea = new TextArea() {
            @Override
            protected void layoutChildren() {
                super.layoutChildren();
                if (caret == null) {
                    final Region content = (Region) lookup(".content");
                    // Looking for the caret path node and add a listener to its bounds to keep track of its position in screen.
                    content.getChildrenUnmodifiable().stream()
                            .filter(node -> node instanceof Path)
                            .map(node -> (Path) node)
                            // Find a more better way to find the caret path node
                            .filter(path -> path.getStrokeWidth() == 1 && path.fillProperty().isBound() && path.strokeProperty().isBound())
                            .findFirst().ifPresent(path -> {
                        path.boundsInLocalProperty().addListener((obs,old,bounds) -> {
                            if (bounds.getWidth() > 0 && bounds.getHeight() > 0) {
                                caretBoundsInScreen = path.localToScreen(bounds);
                            }
                        });
                        caret = path;
                    });
                }
            }
        };
        textArea.setWrapText(true);
        VBox.setVgrow(textArea,Priority.ALWAYS);

        ListView<String> list = new ListView<>();
        list.setPrefSize(150,200);
        list.getItems().addAll("One","Two","Three");
        Popup popup = new Popup();
        popup.setAutoHide(true);
        popup.getContent().addAll(list);

        Button show = new Button("Show ListView");
        show.setOnAction(e->{
            popup.show(caret,caretBoundsInScreen.getMinX(),caretBoundsInScreen.getMaxY());
        });
        root.getChildren().addAll(show,textArea);

        textArea.setText("Lorem ipsum dolor sit amet,consectetur adipiscing elit,sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.");
    }
}

,

使用 Sai 的回答，我创建了自己的解决方案！

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