在海龟文件上运行 SPARQL 查询

如何解决在海龟文件上运行 SPARQL 查询

我正在尝试使用 python 对海龟文件运行 SPARQL 查询，但我的 sparql 返回所有条目，我该如何返回 name="Idham Al-Taif Mahmoud" 的条目？

海龟文件：

<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/hasName> "Idham Al-Taif Mahmoud".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/diedOn> "28 Feb 2017".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/hasAge> "adult".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/hasSex> "male".
<http://example.org/person/a6376-dh3642> <http://dbpedia.org/ontology/diedIn> "Samarra,south of Salah Al-Din".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/hasName> "Shukran Ghanim Hussein".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/diedOn> "26 Feb 2017".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/hasAge> "child".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/hasSex> "male".
<http://example.org/person/a6363-fn3690> <http://dbpedia.org/ontology/diedIn> "Hay Koor,west Mosul".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasName> "Munther Al-Ajaj ".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasMaritalStatus> "married".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasParentalStatus> "parent".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/diedOn> "25 Feb 2017".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasAge> "adult".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/hasSex> "male".
<http://example.org/person/a6348-sz3469> <http://dbpedia.org/ontology/diedIn> "Al-Mazra'a village,Baiji,north of Salah Al-Din".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/hasName> "Shifa Gerdi/Born Shifa Zikri Ibrahim Gerdi".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/diedOn> "25 Feb 2017".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/hasAge> "young adult".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/hasSex> "female".
<http://example.org/person/a6381-xz3480> <http://dbpedia.org/ontology/diedIn> "west Mosul".

python 代码：

import rdflib

filename = "turtle.ttl"


g = rdflib.Graph()

result = g.parse(filename,format='ttl')
print(result)

query = """

SELECT ?person
WHERE {
    ?person <http://dbpedia.org/ontology/hasName> "Idham Al-Taif Mahmoud"
}

"""

g.query(query)
for stmt in g:
    print(stmt)

解决方法

我认为您的问题在于方法。 Here 是一个包含您想要做什么的很好示例的链接。

以下脚本对我有用：

import rdflib
  
filename = "turtle.ttl"


g = rdflib.Graph()

g.parse(filename,format='ttl')

query = """

SELECT ?person
WHERE {
    ?person <http://dbpedia.org/ontology/hasName> "Idham Al-Taif Mahmoud"
}

"""

qres = g.query(query)

for row in qres :
        print("%s" % row)

请注意，我将查询结果分配给了一个新变量 qres，而且 parse 方法是无效的，即它不会像您那样返回值。

最后的 % 符号只是为了打印人类可读的结果，但您可以完全摆脱它们。