如何解决C++ 程序,其中,从用户读取一个六位整数作为输入,并通过 for/While 循环
/编写一个C++程序,从用户那里读取一个六位整数作为输入,并使用循环以words形式输出它的每个数字。/
#include <iostream>
using namespace std;
int main()
{
int number,last_number,count = 0;
cout << "Please enter a six digit number:" << endl;
cin >> number;
while (count < 6)
{
last_number = number % 10;
if (last_number == 0)
cout << "Zero ";
else if (last_number == 1)
cout << "One ";
else if (last_number == 2)
cout << "Two ";
else if (last_number == 3)
cout << "Three ";
else if (last_number == 4)
cout << "Four ";
else if (last_number == 5)
cout << "Five ";
else if (last_number == 6)
cout << "six ";
else if (last_number == 7)
cout << "Seven ";
else if (last_number == 8)
cout << "Eight ";
else if (last_number == 9)
cout << "Nine ";
number = number / 10;
count++;
}
cout << endl;
return 0;
}
当我运行程序时,它输出相反的值,例如我想打印 123456 而不是输出一二三四五六它输出六五四三二一。我该如何解决这个问题?
解决方法
由于数字是从右到左分解的,所以显示的输出是相反的。 有几种方法可以解决这个问题,即您可以使用堆栈来推送输出值并以正确的顺序获取它们。例如,您还可以创建一个字符串,
string number = "";
number = last_number + " " + number;
好吧,您的逻辑中的问题是 last_number = number % 10;
因为当您除以数字时,您会得到最后一个元素,例如,如果将 12345 除以 10,您将得到 5 作为余数,这就是问题出现的地方尝试使用字符串和 for 循环会更容易
#include <iostream>
using namespace std;
int main()
{
string number;
cout << "Please enter a six digit number" << endl;
cin >> number;
for (int i = 0; i < number.length(); i++)
{
if (number[i] == '0')
cout << "Zero ";
else if (number[i] == '1')
cout << "One ";
else if (number[i] == '2')
cout << "Two ";
else if (number[i] == '3')
cout << "Three ";
else if (number[i] == '4')
cout << "Four ";
else if (number[i] == '5')
cout << "Five ";
else if (number[i] == '6')
cout << "six ";
else if (number[i] == '7')
cout << "Seven ";
else if (number[i] == '8')
cout << "Eight ";
else if (number[i] == '9')
cout << "Nine ";
}
return 0;
}
,
last_number=number%10
这行代码给出了数字除以 10 的余数。所以 123%10 应该给你 last_number=3。
使用字符串的答案是正确的。但是,如果您想使用整数,这里有另一种使用递归的方法:
#include<iostream>
using namespace std;
void print_digit(int last_number){
if (last_number == 0)
cout << "Zero ";
else if (last_number == 1)
cout << "One ";
else if (last_number == 2)
cout << "Two ";
else if (last_number == 3)
cout << "Three ";
else if (last_number == 4)
cout << "Four ";
else if (last_number == 5)
cout << "Five ";
else if (last_number == 6)
cout << "six ";
else if (last_number == 7)
cout << "Seven ";
else if (last_number == 8)
cout << "Eight ";
else if (last_number == 9)
cout << "Nine ";
}
void get_digits(int number){
if(number<10){
print_digit(number);
return;
}
get_digits(number/10);
print_digit(number%10);
}
int main(){
int number=12345;
get_digits(number);
}
如果您不想使用递归,您可以使用您现在使用的相同逻辑并将 last_number 值存储在堆栈中。您可以找到更多方式here
,您以相反的顺序得到结果,因为您是通过模数运算 (%) 从末尾提取每个数字。
要以正确的顺序得到答案,您可以先将原始数字反转,然后使用您正在使用的相同逻辑。
....
cin >> number;
int tmp_number = 0; //temporary number to store reverse value of "number"
while ( number > 0 )
{
tmp_number = tmp_number * 10 + number % 10;
number = number / 10;
}
number = tmp_number;
while (count < 6)
....
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