如何解决通过字符串数组创建具有特定键和值的 JSON 树
["storage/","storage/ui/","storage/inventory/","storage/model/","storage/staticmos/","storage/ui/server.js","storage/ui/config.js","storage/ui/elements/","storage/ui/package.json","storage/ui/model/","storage/ui/gulpfile.js","storage/ui/i18n/","storage/ui/Metadata/","storage/ui/index.template.html"]
我的目的是制作一个 json 树,其中每个对象都将包含下一个属性:name
(目录名称/文件名称)、type
(文件或目录)、{{1 }}(实际的数组条目)、path
、id
(仅当类型为目录时!如果目录中没有任何内容则为空数组)
所以返回的值应该是这样的:
children
所以,我现在有两个大问题:
- 使用特定键减少操作对象后返回
- 从目录中区分文件。
这就是我现在得到的:
[
{
id: 1,name: "Inventory",type: "directory",path: "../../elements/storage/Inventory",children: [
{
id: 2,name: "inventory.yaml",type: "file",path: "../../elements/storage/Inventory/inventory.yaml",},],{
id: 3,name: "UI",path: "../../elements/storage/UI",children: [
{
id: 4,name: "Model",path: "../../elements/storage/UI/Model",children: [
{
id: 5,name: "viewmodel",path: "../../elements/storage/UI/Model/viewmodel",children: [],{
id: 6,name: "elements",path: "../../elements/storage/elements",{
id: 7,name: "i18n",path: "../../elements/storage/i18n",{
id: 8,name: "index.template.html",path: "../../elements/storage/index.template.html",{
id: 9,name: "DeviceConnector",path: "../../elements/storage/DeviceConnector",]
解决方法
您可以使用最后一个斜杠并使用它来更改类型。
const
data = ["storage/","storage/ui/","storage/inventory/","storage/model/","storage/staticmos/","storage/ui/server.js","storage/ui/config.js","storage/ui/elements/","storage/ui/package.json","storage/ui/model/","storage/ui/gulpfile.js","storage/ui/i18n/","storage/ui/metadata/","storage/ui/index.template.html"],result = data.reduce((r,path) => {
path.split('\/').reduce((level,name) => {
if (name === '') {
level.type = 'directory';
return;
}
let directory = (level.children = level.children || []).find(q => q.name === name);
if (!directory) level.children.push(directory = { id: '_' + Math.random().toString(36).substr(2,9),name,type: 'file',path });
return directory;
},r);
return r;
},{}).children;
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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