如何解决删除由连接多个表的选择查询获取的行
我写了以下选择:
SELECT r.ID,r.NAME,r.REMARK,u.user_id,u.deadline,u.creation_date,d.NEXT_TEST_DATE,t.TEST_INTERNAL_EXTERNAL FROM reminder r,reminder_users u,device d,device_test t where r.id = u.reminder_id and u.receipt = 0 and (regexp_replace(r.origin_values,'[^0-9]','')) = d.id and d.NEXT_TEST_INT_ID = t.id and t.TEST_INTERNAL_EXTERNAL = 0 and r.NAME like '%Interne%' and r.NAME not like '%Externe%' and u.deadline <> d.NEXT_TEST_DATE_INTERNAL and u.DEADLINE > sysdate GROUP BY r.ID,u.audt_creation_date,d.NEXT_TEST_DATE_INTERNAL,t.TEST_INTERNAL_EXTERNAL ORDER BY u.deadline;
我想做什么:我想删除提醒中的行,这些行是由描述的选择获取的。
我尝试了什么:
DELETE from REMINDER where id in (SELECT r.ID,t.TEST_INTERNAL_EXTERNAL ORDER BY u.deadline);
结果:00907. 00000 - "missing right parenthesis"
我想知道我是否可以通过这种方式基本上删除这些行。我也试过 'exists' 导致同样的错误。
有什么建议吗?提前致谢!
解决方法
从您的子查询中删除 order by 子句,它应该可以工作:
DELETE from BSRMD_REMINDER where id in (SELECT r.ID FROM bsrmd_reminder r,bsrmd_reminder_users u,bsdev_device d,bsdev_device_test t where r.id = u.reminder_id and u.receipt = 0 and (regexp_replace(r.origin_values,'[^0-9]','')) = d.id and d.NEXT_TEST_INT_ID = t.id and t.TEST_INTERNAL_EXTERNAL = 0 and r.NAME like '%Interne%' and r.NAME not like '%Externe%' and u.deadline <> d.NEXT_TEST_DATE_INTERNAL and u.DEADLINE > sysdate GROUP BY r.ID,r.NAME,r.REMARK,u.user_id,u.deadline,u.audt_creation_date,d.NEXT_TEST_DATE_INTERNAL,t.TEST_INTERNAL_EXTERNAL );
或者更好地使用exists:
DELETE from BSRMD_REMINDER
where exists
(
SELECT 1
FROM bsrmd_reminder r,bsdev_device_test t
where r.id = u.reminder_id and u.receipt = 0 and (regexp_replace(r.origin_values,'')) = d.id
and d.NEXT_TEST_INT_ID = t.id and t.TEST_INTERNAL_EXTERNAL = 0 and r.NAME like '%Interne%' and r.NAME not like '%Externe%'
and u.deadline <> d.NEXT_TEST_DATE_INTERNAL and u.DEADLINE > sysdate
AND BSRMD_REMINDER.ID=r.ID
GROUP BY r.ID,t.TEST_INTERNAL_EXTERNAL
);
**请再次检查所有这些连接是否真的有必要。
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