机器人在对同一消息的两种反应做出反应时发送消息

如何解决机器人在对同一消息的两种反应做出反应时发送消息

mstatus = True

for mem in members:
  memberreact = await mem.user.send("do you wish to approve  or decline?\nchoose ⬆️ to approve and ⬇️ to decline!!")

  await memberreact.add_reaction("⬆️")
  await memberreact.add_reaction("⬇️")

  def mcheck1(reaction,user):
    return user == mem.user and reaction.message.id == memberreact.id and str(reaction.emoji) == "⬆️"
  def mcheck2(reaction,user):
    return user == mem.user and reaction.message.id == memberreact.id and str(reaction.emoji) == "⬇️"

  async def mreact1(mstatus):
    #first logic
    if mstatus == True:
      reaction,user = await client.wait_for("reaction_add",check=mcheck1)
      await mem.user.send("you have approved!!")
      mstatus = False
      print(mstatus)
  async def mreact2(mstatus):
    #second logic
    if mstatus == True:
      reaction,check=mcheck2)
      await mem.user.send("you have decline!!")
      mstatus = False
      print(mstatus)
     
  await asyncio.gather(mreact1(mstatus),mreact2(mstatus))

这段代码在对 ⬆️ 做出反应时给我第一个逻辑，并且 在对 ⬇️ 做出反应时给我第二个逻辑 在 相同的消息..但这没有意义，因为 代码中的 mstatus 在最初对 ⬆️ 做出反应时变为 False .. 这段代码有什么问题吗？如果是，请告诉我..

解决方法

你打错了，很简单：

async def mreact1(mstatus):
   if mstatus == True:
      reaction,user = await client.wait_for("reaction_add",check=mcheck1)
      await mem.user.send("you have approved!!")
      mstatus = False ## SHOULD BE TRUE!!!!!
      print(mstatus)