输入字母、符号和负数时验证年龄输入以提示消息

如何解决输入字母、符号和负数时验证年龄输入以提示消息

我想用我在下面写的代码验证输入年龄

cout << "Enter the Age of The " << qty << " Passenger(s) :: ";
for (int i = 1; i <= qty; i++) {
    cout << "\nAge for Passenger " << i << " :: ";
    cin >> age[i];

    while ((!(cin >> age[i])) || (age[i]<=0)) {
        // Explain the error
        cout << "Error: Enter a valid age for Passenger " << i << " : ";
        // Clear the prevIoUs input
        cin.clear();
        // discard prevIoUs input
        cin.ignore(123,'\n');
    }
}

但是，有一个问题。当我输入范围内的年龄时，程序将停止运行。 所以，我想问一下有没有什么有效的方法来验证年龄输入。

解决方法

考虑使用 std::getline 和 std::stringsstream。所以你只是在阅读一行然后尝试解析它。

例如：

#include <iostream>
#include <sstream>

int main(int argc,const char * argv[])
{
    int qty = 10;
    int* age = new int[11];
    std::cout << "Enter the Age of The " << qty << " Passenger(s) :: ";
    for (int i = 1; i <= qty; i++) {
        std::cout << "\nAge for Passenger " << i << " :: ";
        std::string s;
        std::getline(std::cin,s);
        std::stringstream stream(s);

        while ((!(stream >> age[i])) || (age[i]<=0)) {
            // Explain the error
            std::cout << "Error: Enter a valid age for Passenger " << i << " : ";
            std::getline(std::cin,s);
            stream = std::stringstream (s);
        }
    }

    for (int i = 1; i <= qty; i++) {
        std::cout << age[i];
    }

    delete [] age;
    return 0;
}

另请注意，使用 using namespace std 和索引从 1 是不好的模式