如何解决比较元组值记录明智
我有一个有序元组(它是二维的,第 0 列是我的结尾,我想比较它和第 1 列有完整的 url),在“列”[0] 我必须将第一个值与第二个值进行比较,如果它们相同,则将第一个值保存到其他列表并重复。我想将每个项目与以下项目进行比较,无论它们是否相等。
元组:
[('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT240/a-XH0124KP','/a-XH0124KP'),('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT183/a-XH0124KP',('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT173/a-XH0124KP',('https://www.topart-online.com/de/Liguster-Zweig-50cm-mit-Glitter/c-KAT184/a-XM0721','/a-XM0721'),('https://www.topart-online.com/de/3D-Stern-schwarz-mit-Glitter%2C-7%2C5-cm---SUPER-DEAL/c-KAT14/a-XM1633ZW','/a-XM1633ZW'),('https://www.topart-online.com/de/Christbaumschmuck%2C-Zweige%2C-gold-30-cm----SUPER-DEAL/c-KAT14/a-XP0091','/a-XP0091')]
我想比较url中提取的productnumber,因为每个产品都可能在多个url中找到
我的排序尝试:
sized = len(complete_links2) - 1
for index,tuple in enumerate(complete_links2):
index = k
k = index + 1
if k < sized:
while complete_links2[index][1] == complete_links2[k][1]:
k += 1
if complete_links2[index][1] == complete_links2[k][1]:
k -= 1
not_rep_links.append(complete_links2[index])
complete_links3 = [a_tuple[0] for a_tuple in not_rep_links]
我的问题是,有一些独特的链接也会被过滤掉,因为我的逻辑不是很好。
我也尝试过设置,解压元组,但不知道如何继续
解决方法
我还是有点困惑,但这就是你想要的吗?
list_ = [
('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT240/a-XH0124KP','/a-XH0124KP'),('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT183/a-XH0124KP',('https://www.topart-online.com/de/Rose%2C-Micle%2C-kupfer%2C-52cm%2C-Oe-9cm/c-KAT173/a-XH0124KP',('https://www.topart-online.com/de/Liguster-Zweig-50cm-mit-Glitter/c-KAT184/a-XM0721','/a-XM0721'),('https://www.topart-online.com/de/3D-Stern-schwarz-mit-Glitter%2C-7%2C5-cm---SUPER-DEAL/c-KAT14/a-XM1633ZW','/a-XM1633ZW'),('https://www.topart-online.com/de/Christbaumschmuck%2C-Zweige%2C-gold-30-cm----SUPER-DEAL/c-KAT14/a-XP0091','/a-XP0091')
]
products = []
links = []
for item in list_:
if item[1] not in products:
products.append(item[1])
links.append(item[0])
print(links)
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