c++ 将结构推送到向量然后保存到输出文件的问题

如何解决c++ 将结构推送到向量然后保存到输出文件的问题

我摒弃了矢量的想法，经过一番折腾，设法将结构体放入和取出文件。我真的很享受 C++ 的挑战，有很多东西要学！！！

#include <iostream>
#include <fstream>
#include <vector>
using namespace std;

struct Account_query
{
public:
    char name[50];
    char number[50];
};

void AddRecord(Account_query* aq)
{
    ofstream fout;
    fout.open("Records.out",ios::app | ios::out | ios::binary);
    cout << "Enter name: ";
    cin >> aq->name;
    cout << "Enter account number: ";
    cin >> aq->number;
    fout.write( reinterpret_cast<const char *>( &(*aq) ),sizeof(Account_query) );
    fout.close();
}
void ShowRecord()
{
    Account_query aq;
    //std::memset(&aq,sizeof(aq));
    ifstream inf;
    inf.open("Records.out",ios::binary);
    if(!inf)
    {
        cout << "Problem opening"<<endl;
    }
    cout <<"####Data Out###"<<endl;
    while(!inf.eof())
    {
        inf.read( reinterpret_cast<char *>(&aq.name),sizeof(Account_query::name));
        inf.read( reinterpret_cast<char *>(&aq.number),sizeof(Account_query::number));
        cout << "Name is: " << aq.name << "Account is: " << aq.number <<endl;
    }
}

int main(int argc,const char * argv[]) {
    
    vector<Account_query> list;
    
    cout << "Welcome to Jizz Bank\n";
    cout << "Enter one of the following options then press enter\n";
    cout << "-----------------------------------\n";
    cout << "1) Add Record \n";
    cout << "2) Show Records \n";
    cout << "3) Search Record \n";
    cout << "4) Edit Record \n";
    cout << "5) Delete Record \n";
    cout << "-----------------------------------\n";
    cout << "Enter your choice: ";
    
    int x;
    cin >>x;
    
    Account_query a;
    Account_query *p = &a;
    
    switch(x)
    {
        case 1:{
            
            AddRecord(p);//got the data for object Now
            break;
        }
        case 2:{
            ShowRecord();
            break;
        }
        default:{
            exit(0);
        }
    }
    return 0;
}

以前的条目如下... 我正在尝试编写一个控制台程序来学习 C++。 在 switch 的情况 1 中，我正在动态创建一个结构，然后将它连同对向量的引用一起发送到一个函数。 这个想法是输入一些简单的数据来填充结构，然后将其推送到向量上，然后将其写入文件（二进制）。 问题似乎是：

fout.write(static_cast<char*> (*it),sizeof(Account_query));

我明白了，无法在 Xcode 中从类型“Account_query”转换为指针类型“char *”。 我试过 reinterpret_cast 等等，但这也不起作用。 真的很感激任何帮助， LD。

#include <iostream>
#include <fstream>
#include <vector>
using namespace std;

struct Account_query
{
public:
    char name[50];
    char number[50];
};

void AddRecord(Account_query* aq,vector<Account_query>& list)
{
    ofstream fout;
    fout.open("Records.bank",ios::binary | ios::out);
    cout << "Enter name: ";
    cin >> aq->name;
    cout << "Enter account number: ";
    cin >> aq->number;
    list.push_back(*aq);
    
    for (vector<Account_query>::iterator it=list.begin(); it != list.end(); ++it)
    {
        fout.write(static_cast<char*> (*it),sizeof(Account_query));
    }
    fout.close();
}
void ShowRecord()
{
   //Todo
   
}

int main(int argc,const char * argv[]) {
    
    vector<Account_query> list;
    
    cout << "Welcome to Jizz Bank\n";
    cout << "Enter one of the following options then press enter\n";
    cout << "-----------------------------------\n";
    cout << "1) Add Record \n";
    cout << "2) Show Records \n";
    cout << "3) Search Record \n";
    cout << "4) Edit Record \n";
    cout << "5) Delete Record \n";
    cout << "-----------------------------------\n";
    cout << "Enter your choice: ";
    
    int x;
    cin >>x;
    
    switch(x)
    {
        case 1:{
            Account_query* a = new Account_query;
            AddRecord(a,list);//got the data for object Now
            break;
        }
        case 2:{
            cout<<"do Nowt yet"<<endl;
            break;
        }
        default:{
            exit(0);
        }
    }
    return 0;
}

解决方法

不要给自己找麻烦。首先使用 std::string，然后只需使用 operator<< 将字符串放入文件中（并从中读取）。例如

#include <string>
#include <iostream>
#include <fstream>

struct AccountQuery
{
    std::string name;
    std::string number;
};

AccountQuery AddRecord()
{
    AccountQuery aq;
    std::cout << "Enter name: ";
    std::cin >> aq.name;
    std::cout << "Enter account number: ";
    std::cin >> aq.number;
    {
        std::ofstream fout("Records.out",std::ios::app | std::ios::binary);
        fout << aq.name << " " << aq.number << " "; // spaces for simple separation. 
    }
    return aq;
}
void ShowRecord()
{
    AccountQuery aq;
    std::ifstream fin("Records.out",std::ios::binary);
    if(!fin)
    {
        std::cerr << "Problem opening file.\n";
        return;
    }
    std::cout << "####Data Out###\n";
    while(fin >> aq.name && fin >> aq.number) {
        std::cout << "Name is: " << aq.name << ",Account is: " << aq.number << '\n';
    }
}

int main() {
    std::cout
       << "Welcome to Jizz Bank\n"
       << "Enter one of the following options then press enter\n"
       << "-----------------------------------\n"
       << "1) Add Record\n"
       << "2) Show Records\n"
       << "3) Search Record\n"
       << "4) Edit Record\n"
       << "5) Delete Record\n"
       << "6) Exit\n"
       << "-----------------------------------\n";
    
    bool loop = true;
    while(loop) {
        std::cout << "Enter your choice: ";
        int choice;
        std::cin >> choice;
        switch(choice)
        {
            case 1: {
                AddRecord();//return value unused?
                break;
            }
            case 2: {
                ShowRecord();
                break;
            }
            case 6: {
                loop = false;
                break;
            }
            default: {
                // nothing,could be omitted
                break;
            }
        }
    }
}