Laravel 8：将工厂属性传递给子关系

如何解决Laravel 8：将工厂属性传递给子关系

我们目前正在开发一个 Laravel 8 应用程序。我们正在尝试创建工厂来为基于手动/开发人员的应用程序测试创建一些虚拟数据。

我的主要数据库播种机的当前代码如下：

class DatabaseSeeder extends Seeder
{

    public function run()
    {
        $this->call([
            UserTableSeeder::class,]);
        \App\Models\User::factory(10)->create();
        \App\Models\Activity::factory(5)->create();

/* 1. try
        $tenFact = \App\Models\Tenant::factory(2)->has(
            \App\Models\Project::factory(2)->state(
                function (array $attributes,\App\Models\Tenant $tenant) {
                    return ['tenant_id' => $attributes['id']];
                } 
            )->hasTasks(5)->hasLocation()
        )->hasContracts(3)->create();

        */
        
/* Currently being used: */
        \App\Models\Tenant::factory(10)->has(
            \App\Models\Project::factory(5)->hasTasks(5)->hasLocation()
            )->hasContracts(3)->create();

    }

ProjectFactory.php：

class ProjectFactory extends Factory
{

    protected $model = Project::class;

    public function definition()
    {
        return [
            'name' => 'Projekt: '. $this->faker->name,'budget' => $this->faker->randomDigitNotNull*1000,'progress' => $this->faker->randomDigitNotNull*10,'budget_used' => $this->faker->randomDigitNotNull*50,//'tenant_id' => Tenant::factory(),'location_id' => Location::factory()->hasTenant(1),];
    }
}

LocationFactory.php：

class LocationFactory extends Factory
{

    protected $model = Location::class;

    public function definition()
    {
        return [
            'name' => 'Standort: ' . $this->faker->company,'street' => $this->faker->streetName,'house_number' => $this->faker->buildingNumber,'house_addition' => $this->faker->secondaryAddress,'zip' => $this->faker->postcode,'city' => $this->faker->city,'tenant_id' => Tenant::factory(),];
    }
}

我们的关系是这样的：

Tenant 
  |-- Project (has: tenant_id,but also has location_id)
  |   | -- Task (has: project_id)
  |-- Locations (has: tenant_id)
  |-- Contracts (has: tenant_id)

使用上面命名的 Tenant-Factory 创建数据集时，会发生以下情况：

• Tenant->id 被传递给 Project(tenant_id) 但是：Tenant->id 没有传递给 Location（这取决于租户 ID，但也用于项目）。

我们如何将\App\Models\Tenant::factory(10) 的id 传递给Project::factory(5)->hasTasks(5)->hasLocation()？

此外，我们确实遇到了问题，即使我们请求 10 个租户，我们也会得到大约 60 个，因为 Location/Project 在它们应该使用现有对象时创建了新对象。

解决方法

class ProjectFactory extends Factory
{
 $location_ids = App\Models\Location::pluck('id')->toArray();

    protected $model = Project::class;

    public function definition()
    {
        return [
            'name' => 'Projekt: '. $this->faker->name,'budget' => $this->faker->randomDigitNotNull*1000,'progress' => $this->faker->randomDigitNotNull*10,'budget_used' => $this->faker->randomDigitNotNull*50,//'tenant_id' => Tenant::factory(),'location_id'=> $faker->randomElement($location_ids),];
    }
}

class LocationFactory extends Factory
{
    $tenant_ids = App\Models\Tenant::pluck('id')->toArray();
    protected $model = Location::class;

    public function definition()
    {
        return [
            'name' => 'Standort: ' . $this->faker->company,'street' => $this->faker->streetName,'house_number' => $this->faker->buildingNumber,'house_addition' => $this->faker->secondaryAddress,'zip' => $this->faker->postcode,'city' => $this->faker->city,'tenant_id'=> $faker->randomElement($tenant_ids),];
    }
}

,

我放弃了使用 Tenant-Factory 的链式用法 - 我最终使用了一些 for-Loop，通过使用 laravel 的 for() 和 state() 方法将相关对象连接到每个用户：

       for ($i=0; $i < 10 ; $i++) { 
            $tenant = \App\Models\Tenant::factory()->hasContracts(3)->create();
            for ($j=0; $j < 5; $j++) { 
                $location = \App\Models\Location::factory(1)->for($tenant)->create();
                $project = \App\Models\Project::factory(1)->state([
                    'location_id' => $location->first()['id'],'tenant_id' => $tenant['id']])->hasTasks(5)->create();
            }
        }