计算时间戳的差异并跳过NULL

如何解决计算时间戳的差异并跳过NULL

如何跳过第一行来计算差异平均值？ “WHERE”过滤器不起作用（错误：WHERE 子句中不允许使用分析函数）

为什么我可以用“557186”跳过第一个值？
是否可以声明“Unit”以便稍后将这个变量用于“WHERE”？

SELECT
  FORMAT_TIMESTAMP("%F",Timestamp) AS Date,FORMAT_TIMESTAMP("%r",Timestamp) AS Unit,LAG(FORMAT_TIMESTAMP("%r",Timestamp)) OVER (ORDER BY FORMAT_TIMESTAMP("%r",Timestamp)) AS CycleTimePreValue,CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64)-LAG(CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64)) OVER (ORDER BY CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64)) AS CycleTimePreValueSeconds,FROM
  `wh-lr-sk.Quality.Retouren_IMPORT`
  # WHERE (CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64))) < 1000
ORDER BY
  Unit
LIMIT
  10

解决方法

要“声明”单位，您可以使用 CTE（通用表表达式）。

with time_lags as (
SELECT
  FORMAT_TIMESTAMP("%F",Timestamp) AS Date,FORMAT_TIMESTAMP("%R",Timestamp) AS Unit,LAG(FORMAT_TIMESTAMP("%R",Timestamp)) OVER (ORDER BY FORMAT_TIMESTAMP("%R",Timestamp)) AS CycleTimePreValue,CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64)-LAG(CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64)) OVER (ORDER BY CAST(FORMAT_TIMESTAMP("%s",Timestamp) AS INT64)) AS CycleTimePreValueSeconds,FROM
  `wh-lr-sk.Quality.Retouren_IMPORT`
)
SELECT
    *
FROM time_lags
WHERE Unit < 1000
AND CycleTimePreValue IS NOT NULL
ORDER BY
  Unit
LIMIT
  10

要删除我刚刚添加的空值，请将 AND CycleTimePreValue IS NOT NULL 添加到 where 子句中。