如何使用 PYSIMPLEGUI 在文本 wdiget 中显示函数的输出？

如何解决如何使用 PYSIMPLEGUI 在文本 wdiget 中显示函数的输出？

如何在弹出的文本输出中显示函数的结果？

import PySimpleGUI as sg

FILMS = [["There will be blood","Paul Thomas Anderson",2007],["Lion King","Rob Minkoff",1994],["Toy Story","Josh Cooley",1995],["Monty Python's Life of Brian","Terry Jones",1979],["Die Hard","John McTiernan",1988],["Rocky","John G. Avildsen",1976]]


def listprint():
    for i in range (len(FILMS)):
        print(FILMS[i][0])

event,values = sg.Window('Find a film',[[sg.Text('Are you ready:')],[sg.B("OK",key="-OK-"),sg.B("Return",key="-Return-")] ]).read(close=True)

if event == '-OK-':
    sg.popup('Film names will be printed in the python output:',command = listprint)

解决方法

只需将结果传递给 sg.popup，但使用 * 解包列表/元组。有时，它看起来不太好，您可以使用用户定义的弹出窗口来显示它们。

import PySimpleGUI as sg

def film_name():
    return [item[0] for item in FILMS]

FILMS = [
    ["There will be blood","Paul Thomas Anderson",2007],["Lion King","Rob Minkoff",1994],["Toy Story","Josh Cooley",1995],["Monty Python's Life of Brian","Terry Jones",1979],["Die Hard","John McTiernan",1988],["Rocky","John G. Avildsen",1976],]

layout = [
    [sg.Text('Are you ready:')],[sg.B("OK"),sg.B("Return")],]

window = sg.Window('Find a film',layout,finalize=True)

while True:
    event,values = window.read()
    if event in (sg.WINDOW_CLOSED,'Return'):
        break
    elif event == 'OK':
        sg.popup('Film names will be printed in the python output:',*film_name())
    print(event,values)

window.close()