如何解决如何在此处传递 Id错误 put() 缺少 1 个必需的位置参数:'request'在表单模板 Django
urls.py
from django.urls import path
from . import views
app_name = "poll"
urlpatterns = [
path('',views.index,name="index"),# listing the polls
path('<int:id>/edit/',views.put,name='poll_edit'),]
views.py
def put(self,request,id):
# print("catching error ") error before this line
question = get_object_or_404(Question,id=id)
poll_form = PollForm(request.POST,instance=question)
choice_forms = [ChoiceForm(request.POST,prefix=str(
choice.id),instance=choice) for choice in question.choice_set.all()]
if poll_form.is_valid() and all([cf.is_valid() for cf in choice_form]):
new_poll = poll_form.save(commit=False)
new_poll.created_by = request.user
new_poll.save()
for cf in choice_form:
new_choice = cf.save(commit=False)
new_choice.question = new_poll
new_choice.save()
return redirect('poll:index')
context = {'poll_form': poll_form,'choice_forms': choice_forms}
return render(request,'polls/edit_poll.html',context)
edit_poll.html
{% extends 'base.html' %}
{% block content %}
<form method="PUT" >
{% csrf_token %}
<table class="table table-bordered table-light">
{{poll_form.as_table}}
{% for form in choice_forms %}
{{form.as_table}}
{% endfor %}
</table>
<button type="submit" class="btn btn-warning float-right">Update</button>
</form>
{% endblock content %}
这是错误
line 181,in _get_response
response = wrapped_callback(request,*callback_args,**callback_kwargs)
Exception Type: TypeError at /polls/9/edit/
Exception Value: put() missing 1 required positional argument: 'request'
我知道我不是在 html 中传递参数,但我不知道如何在 html 中传递 id 参数,请帮助我 任何单行代码类似于 default(由 Django 传递的上下文)
解决方法
您正在定义一个简单的函数,而不是类中的方法,因此您应该删除 self
参数:
# no self ↓
def put(request,id):
# …
请注意,您对 choice_forms
所做的基本上就是 FormSet
does [Django-doc]。
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。