如何解决A 列上的 SQL 内连接并比较 B 列中的值
我确定或者希望有一种简单的方法可以做到这一点。下面是我最近的尝试。查询应该只返回一行，但我得到 31。
查询：
`select distinct a.[EC CERS],a.[EC Tank ID],[CIW Tank ID]
from #tempectank a
inner join #tempciwtank b on a.[EC CERS] = b.[CIW CERS]
where a.[EC Tank ID] <> b.[CIW Tank ID]`
表格数据：
表A
| EC CERS | EC 坦克 ID |
|---|---|
| 100338 | 1 |
| 100338 | 2 |
| 100338 | 3 |
表 B
| CIW CERS | CIW 坦克 ID |
|---|---|
| 100338 | 001 |
| 100338 | 2 |
| 100338 | 3 |
表格架构
create table #tempectank(
s int IDENTITY (1,1),[EC CERS] varchar(9),[EC Tank ID] varchar(255)
)
我需要查询返回一行，最好显示 EC CERS、EC Tank ID 和 CIW Tank ID。
解决方法
如果是导致 ziros 的问题，您可以使用此解决方案：
如果您的 ID 中没有数字，这将不起作用
Select a.[EC CERS],a.[EC Tank ID],b.[CIW Tank ID]
from #tempectank a
inner join #tempciwtank b
on a.[EC CERS] = b.[CIW CERS]
and a.[EC Tank ID] <> b.[CIW Tank ID]
and cast(a.[EC Tank ID] as int ) = cast(b.[CIW Tank ID] as int)
实际上另一种解决方案是显示那些您找不到匹配项的内容：
select * from #tempectank a
where not exists (select 1 from #tempciwtank b
where a.[EC CERS] = b.[CIW CERS]
and a.[EC Tank ID] = b.[CIW Tank ID]
)
and exists (select 1 from #tempciwtank b where a.[EC CERS] = b.[CIW CERS])
如果你想并排显示不匹配的案例，你必须从两边找到不匹配的实例：
select * from (
select * from #tempectank a
where not exists (select 1 from #tempciwtank b
where a.[EC CERS] = b.[CIW CERS]
and a.[EC Tank ID] = b.[CIW Tank ID]
)
and exists (select 1 from #tempciwtank b where a.[EC CERS] = b.[CIW CERS])
) a
join (
select * from #tempciwtank b
where not exists (select 1 from #tempectank a
where a.[EC CERS] = b.[CIW CERS]
and a.[EC Tank ID] = b.[CIW Tank ID]
)
and exists (select 1 from #tempectank a where a.[EC CERS] = b.[CIW CERS])
)b
on a.[EC CERS] = b.[CIW CERS]
如果您想要 a.[EC CERS] = b.[CIW CERS] 和 a.[EC Tank ID] b.[CIW Tank ID] 的行，请尝试以下操作：
Select a.[EC CERS],b.[CIW Tank ID]
from #tempectank a
inner join #tempciwtank b
on a.[EC CERS] = b.[CIW CERS]
and a.[EC Tank ID] <> b.[CIW Tank ID]
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