如何解决有没有办法简化这个功能?
我有一个函数,它返回一个带有坐标和对象正在看的方向的字符串。 但我真的不喜欢函数的长度,我想缩短它。我不知道我能做些什么来缩短它。有人可以帮我吗?
函数如下所示:
public string Execute(string text)
{
var letters = text.tochararray().ToList();
foreach (var letter in letters)
{
if (letter == 'R')
{
switch(direction)
{
case "N":
direction = "E";
break;
case "E":
direction = "S";
break;
case "S":
direction = "W";
break;
case "W":
direction = "N";
break;
}
}
if (letter == 'L')
{
switch (direction)
{
case "N":
direction = "W";
break;
case "E":
direction = "N";
break;
case "S":
direction = "E";
break;
case "W":
direction = "S";
break;
}
}
if (letter == 'M')
{
switch (direction)
{
case "N":
positionY++;
break;
case "E":
positionX++;
break;
case "S":
positionY--;
break;
case "W":
positionX--;
break;
}
}
if (letter == 'B')
{
switch (direction)
{
case "N":
positionY--;
break;
case "E":
positionX--;
break;
case "S":
positionY++;
break;
case "W":
positionX++;
break;
}
}
}
return $"{positionX}:{positionY}:{direction}";
}
这里的文本只是一个无用的文本,因此我可以提交我的问题,因为我的代码太长并且 Stackoverflow 将问题识别为主要代码,因此我必须编写更多没有代码括号的文本才能提交问题.您不必阅读此文本,因为它没有任何目的。
解决方法
尝试以下操作:
string text = "";
var letters = text.ToCharArray().ToList();
Dictionary<char,Dictionary<string,string>> dict = new Dictionary<char,string>>() {
{'R',new Dictionary<string,string>() { { "N","E" },{ "E","S" },{ "S","W" },{ "W","N" }}},{'L',"N" },"S" }}},{'M',"AY" },"AX" },"SY" },"SX" }}},{'R',"SX" },{ "N","AX" }}}
};
string direction = "";
int positionX = 0;
int positionY = 0;
foreach (var letter in letters)
{
string value = dict[letter][direction];
switch (value)
{
case "SX":
positionX--;
break;
case "SY":
positionY--;
break;
case "AX":
positionX++;
break;
case "AY":
positionY++;
break;
case "N":
direction = value;
break;
case "E":
direction = value;
break;
case "S":
direction = value;
break;
case "W":
direction = value;
break;
}
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