如何解决是否可以遍历数组中的每个图像 src 并将其显示在您的网页上?
我正在尝试遍历数组中定义的每个单独的图像源。创建一个新的图像元素,该元素将设置图像 1、图像 2 等的属性 src,直到数组中不再有新的图像源可以循环并将其显示到网页。
const u = document.querySelector(".divs:nth-child(3)");
const a = [
{
name: "BBQ Becky",img: "https://assets.codepen.io/1179484/bbqbecky_1.jpg"
},{
name: "Permit Patty",img: "https://assets.codepen.io/1179484/permitpatty_1.jpg"
},{
name: "Pool Patrol Puala",img: "https://assets.codepen.io/1179484/poolpatrolpaula_1.jpg"
},{
name: "Wake Up Suzie",img: "https://assets.codepen.io/1179484/wakeupsuzie_1.jpg"
},{
name: "ID Adam",img: "https://assets.codepen.io/1179484/idadam_1.jpg"
}
];
for (i = 0; i < a.length; i++) {
var image = document.createElement("img");
image.setAttribute("src",a[i].img);
u.appendChild(image);
}
* {
margin: 0;
padding: 0;
}
#s1 {
height: 100vh;
widht: 100vw;
background: salmon;
}
img {
height: 100px;
}
<section id="s1">
<div class="divs"></div>
<div class="divs"></div>
<div class="divs"></div>
</section>
解决方法
这应该可以解决问题:
const a = [
{
name: "BBQ Becky",img: "https://assets.codepen.io/1179484/bbqbecky_1.jpg",},{
name: "Permit Patty",img: "https://assets.codepen.io/1179484/permitpatty_1.jpg",{
name: "Pool Patrol Puala",img: "https://assets.codepen.io/1179484/poolpatrolpaula_1.jpg",{
name: "Wake Up Suzie",img: "https://assets.codepen.io/1179484/wakeupsuzie_1.jpg",{
name: "ID Adam",img: "https://assets.codepen.io/1179484/idadam_1.jpg",];
const renderImages = (arr) => {
for (let i in arr) {
let image = document.createElement("img");
image.setAttribute("src",arr[i].img);
document.body.appendChild(image);
}
};
renderImages(a);
您只需要像这样取消引用 a[i].img
部分:
const u = document.querySelector(".divs:nth-child(3)");
const a = [
{
name: "BBQ Becky",img: "https://assets.codepen.io/1179484/bbqbecky_1.jpg"
},img: "https://assets.codepen.io/1179484/permitpatty_1.jpg"
},img: "https://assets.codepen.io/1179484/poolpatrolpaula_1.jpg"
},img: "https://assets.codepen.io/1179484/wakeupsuzie_1.jpg"
},img: "https://assets.codepen.io/1179484/idadam_1.jpg"
}
];
for (i = 0; i < a.length; i++) {
var image = document.createElement("img");
image.setAttribute("src",a[i].img);
u.appendChild(image);
}
* {
margin: 0;
padding: 0;
}
#s1 {
height: 100vh;
widht: 100vw;
background: salmon;
}
img {
height: 100px;
}
<section id="s1">
<div class="divs"></div>
<div class="divs"></div>
<div class="divs"></div>
</section>
使用 forEach
const u = document.querySelector(".divs:nth-child(3)");
const a = [
{
name: "BBQ Becky",img: "https://assets.codepen.io/1179484/idadam_1.jpg"
}
];
a.forEach(o => {
let image = document.createElement("img");
image.setAttribute("src",o.img);
u.appendChild(image);
});
* {
margin: 0;
padding: 0;
}
#s1 {
height: 100vh;
widht: 100vw;
background: salmon;
}
img {
height: 100px;
}
<section id="s1">
<div class="divs"></div>
<div class="divs"></div>
<div class="divs"></div>
</section>
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