Python 中的 Connect4 - Pieces 不会掉进板子里

如何解决Python 中的 Connect4 - Pieces 不会掉进板子里

我正在用 Python 编写 Connect4。我的问题是 player_one 和 player_two 的功能似乎不起作用，因此在要求玩家提供输入后，没有棋子掉到棋盘上。我也想知道我在玩家掉落后返回棋盘的代码是否正确；我怀疑我目前的代码没有返回更新了玩家棋子的棋盘，但我是新的，我不知道该怎么做。

请看！

def field(field):
    for w in range(14):
        if w % 2 == 0:
            usable_w = int(w/2)
            for h in range(15):
                if h % 2 == 0:
                    usable_h = int(h/2)
                    if h != 14:
                        print(field[usable_h][usable_w],end="")
                    else:
                        print(" ")
                else:
                    print("|",end="")
        else:
            print("_"*13)


PlayField = [[" "," "," "],[" "," "]]
field(PlayField)


def player_one(field):
    MoveColumn = int(input("Enter the column 1 - 7\n"))
    MoveRow = 6
    for row in PlayField:
        if MoveColumn >= 1 and MoveColumn <= 7:
            if PlayField[MoveColumn-1][MoveRow] == " ":
                    PlayField[MoveColumn-1][MoveRow] = "X"
                    break
            MoveRow -= 1
            return field(PlayField)
        else:
            print("Column outside range,please enter valid move")

def player_two(field):
    MoveColumn = int(input("Enter the column 1 - 7\n"))
    MoveRow = 6
    for row in PlayField:
        if MoveColumn >= 1 and MoveColumn <= 7:
            if PlayField[MoveColumn-1][MoveRow] == " ":
                    PlayField[MoveColumn-1][MoveRow] = "O"
                    break
            MoveRow -= 1
            return field(PlayField)
        else:
            print("Column outside range,please enter valid move")

def launch_play():
    while True:
        Player = 1
        print("Player's turn",Player)
        player_one(field)
        player_two(field)

launch_play()

解决方法

好吧，您的 player_... 函数包含合适的语句，但顺序不合适；并且由于它们对全局 PlayField 进行操作，因此返回它毫无意义。除此之外，它有两个几乎相同的功能是丑陋的。一种重新排列的变体，其中玩家一和玩家二之间的唯一区别作为参数传递（而不是无用的 field），如您所料：

def player(xo):
    while (MoveColumn := int(input("Enter the column 1 - 7\n"))) < 1 or \
                                                      MoveColumn > 7:
        print("Column outside range,please enter valid move")
    MoveRow = 6
    for row in PlayField:
        if PlayField[MoveColumn-1][MoveRow] == " ":
            PlayField[MoveColumn-1][MoveRow] = xo
            field(PlayField)
            break
        MoveRow -= 1

在您的 launch_play 循环中，您现在可以调用

        player('X')
        player('O')

现在由您通过检查游戏何时结束来完成程序。

,

我想出了两个解决方案（在你修改代码之前）来防止玩家轮到改变，但都行不通：

def player(xo):
    while MoveColumn := int(input("Enter the column 1 - 7\n")):
    MoveRow = 6
    for row in PlayField:
        if PlayField[MoveColumn-1][MoveRow] == " ":
            PlayField[MoveColumn-1][MoveRow] = xo
            field(PlayField)
            break
            Return True
        MoveRow -= 1
    else:
       print("Column outside range,please enter valid move")
       Return False

def launch_play():
    while True:
        Player = 'X'
        print("Player's turn",Player)
        player('X')
        Player = '0'
        print("Player's turn",Player)
        player('0')

launch_play()

另一种解决方案是在播放器函数中引入播放器变量（也没有用）：

 def player(xo):
    while MoveColumn := int(input("Enter the column 1 - 7\n")):
    MoveRow = 6
    Player = 'X'
    for row in PlayField:
        if PlayField[MoveColumn-1][MoveRow] == " ":
            PlayField[MoveColumn-1][MoveRow] = xo
            field(PlayField)
            break
        MoveRow -= 1
        Player = '0'
    else:
       print("Column outside range,please enter valid move")