溢出错误：Python int 太大，无法使用 openpyxl.load_workbook(filename, keep_vba=True) 转换为 C long

如何解决溢出错误：Python int 太大，无法使用 openpyxl.load_workbook(filename, keep_vba=True) 转换为 C long

for clid in ClientID:
        filename = path_xlsx.replace('/','\\') + '\\' + str(ClientID[clid])
        # print(filename)
        
        for i in range(len(csv)):
            if str(csv.loc[i,'ClientID']) == clid:
                
                book = openpyxl.load_workbook(filename,keep_vba=True)

我在下面有这个错误：

Excel 名称（文件名是：12149.xlsm）

另一个相同的excel，但在内部进行了一些修改可以工作，只有这个不想打开

例如仅使用此代码：

import openpyxl
global book

filename='C:/Users/victor/12149.xlsm'
book = openpyxl.load_workbook(filename,keep_vba=True)

我也犯了同样的错误：

def from_excel(value,offset=CALENDAR_WINDOWS_1900):
    if value is None:
        return
    if 1 < value < 60 and offset == CALENDAR_WINDOWS_1900:
        value += 1
    parts = list(jd2gcal(MJD_0,value + offset - MJD_0))
    _,fraction = divmod(value,1)
    jumped = (parts[-1] == 0 and fraction > 0)
    diff = datetime.timedelta(days=fraction)

    if 0 < abs(value) < 1:
        return days_to_time(diff)
    if not jumped:
        return datetime.datetime(*parts[:3]) + diff
    else:
        return datetime.datetime(*parts[:3] + [0])