如何解决如何使用 Pygame 计算鼠标速度?
import pygame
import datetime
with open('textdatei.txt','a') as file:
pygame.init()
print("Start: " + str(datetime.datetime.Now()),file=file)
screen = pygame.display.set_mode((640,480))
clock = pygame.time.Clock()
BG_COLOR = pygame.Color('gray12')
done = False
while not done:
# This event loop empties the event queue each frame.
for event in pygame.event.get():
# Quit by pressing the X button of the window.
if event.type == pygame.QUIT:
done = True
elif event.type == pygame.MOUSEBUTTONDOWN:
# MOUSEBUTTONDOWN events have a pos and a button attribute
# which you can use as well. This will be printed once per
# event / mouse click.
print('In the event loop:',event.pos,event.button)
print("Maus wurde geklickt: " + str(datetime.datetime.Now()),file=file)
# Instead of the event loop above you Could also call pygame.event.pump
# each frame to prevent the window from freezing. Comment it out to check it.
# pygame.event.pump()
click = pygame.mouse.get_pressed()
mousex,mousey = pygame.mouse.get_pos()
print(click,mousex,mousey,file=file)
screen.fill(BG_COLOR)
pygame.display.flip()
clock.tick(60) # Limit the frame rate to 60 FPS.
print("Ende: " + str(datetime.datetime.Now()),file=file)
您好,我是 Pygame 的新手,现在,我的程序可以跟踪鼠标坐标并创建点击时间。但我想计算鼠标从一次点击到下一次点击的速度(以每秒像素为单位)。
提前致谢。
解决方法
使用 pygame.time.get_ticks()
返回自调用 pygame.init()
以来的毫秒数。
计算 2 次点击之间的 Euclidean distance 并将其除以时间差:
import math
prev_time = 0
prev_pos = (0,0)
click_count = 0
done = False
while not done:
# This event loop empties the event queue each frame.
for event in pygame.event.get():
# Quit by pressing the X button of the window.
if event.type == pygame.QUIT:
done = True
elif event.type == pygame.MOUSEBUTTONDOWN:
act_time = pygame.time.get_ticks() # milliseconds
act_pos = event.pos
if click_count > 0:
dt = act_time - prev_time
dist = math.hypot(act_pos[0] - prev_pos[0],act_pos[1] - prev_pos[1])
speed = 1000 * dist / dt # pixle / seconds
print(speed,"pixel/second")
prev_time = act_time
prev_pos = act_pos
click_count += 1
# [...]
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