雪花 JavaScript 程序如何从不在阶段的对象更新字段？

如何解决雪花 JavaScript 程序如何从不在阶段的对象更新字段？

我正在尝试在 SNowflake 上执行 JavaScript 过程，以使用 JavaScript 数组中的相关值更新表。

假设我有下表：

并拥有这个数组：

var arr = {"gender_value": "Gender","age_range": "Age Range"}

所以我更新后的表格的最终结果是：

我尝试了类似的东西：

var query = "
    MERGE INTO mytable m
    USING (SELECT * FROM "+arr+" )
";

但我认为如果对象不在阶段，就不可能从对象中进行 SELECT。

解决方法

您将不得不在 SQL 中解析您的数组以获取 MERGE 的结构。另一种选择是将数组存储在临时表中。但我没有看到任何问题让它起作用，请看我的例子：

create or replace table so_test
(
question_name varchar,answer varchar,question_label varchar
);

insert into so_test values ('gender_value','Female',null),('age_range','>60',null);

merge into so_test
using 
(
select 
g.key as join_key,g.value as join_value
from  
(
select parse_json(column1) as arr from values ('{"gender_value": "Gender","age_range": "Age Range"}') 
) x,lateral flatten(input => x.arr) g
)src
on so_test.question_name = src.join_key
when matched then update
set question_label = src.join_value;

--proc example
CREATE OR REPLACE PROCEDURE "ARRAY_TEST_SP"(sp_input varchar)
RETURNS VARCHAR(16777216)
LANGUAGE JAVASCRIPT
EXECUTE AS OWNER
AS 
$$
var v_array = SP_INPUT;
var v_merge = `merge into so_test
using 
(
select 
g.key as join_key,g.value as join_value
from  
(
select parse_json(column1) as arr from values (?) 
) x,lateral flatten(input => x.arr) g
)src
on so_test.question_name = src.join_key
when matched then update
set question_label = src.join_value;`;
var v_stmt = snowflake.createStatement( 
  {
  sqlText:  v_merge,binds:[v_array] 
  }
);
try {
        v_stmt.execute()
        return "Succeeded.";   // Return a success/error indicator.
        }
    catch (err)  {
        return "Failed: " + err;   // Return a success/error indicator.
        }
$$;

call ARRAY_TEST_SP('{"gender_value": "Gender","age_range": "Age Range"}');