编译代码时不显示最后一个员工数据

如何解决编译代码时不显示最后一个员工数据

我正在尝试获取最后一名员工 Bob Hu 的数据。但出于某种原因，它不想出现。有谁知道我做错了什么。？我尝试将计算/显示代码放入 function() 并在您当前计算/显示数据的位置以及 while() 终止后调用它。但我认为我做错了。请帮忙 这是我的代码。

#include <iostream>
#include <string>
#include <fstream>
using namespace std;
void find_pay(string x)
{
    ifstream inputFile;
    string filename;
    
    // Get the filename from the user.
    cout << "Enter the filename: ";
    cin >> filename;

    // Open the file.
    inputFile.open(filename);

    // If the file successfully opened,process it.
    if(inputFile.is_open())
    {
            string data_record,prev,data_name,data_hour;
            double total = 0;
        
            while(getline(inputFile,data_record))
            {
                data_name = data_record.substr(0,30);
                data_hour = data_record.substr(31,2);
                if(prev.compare(data_name)!= 0 )
                {
                    //Calculate the gross pay,tax,net pay
                    float gross_pay = 18 * total;
                    float tax = (12 * gross_pay)/100;
                    float net_pay = gross_pay - tax;
                    if(total!= 0)
                        cout << "Employee:" << prev << "\n" "Total Hours: " << total << " Gross Pay: $ " << gross_pay << " Tax " << tax << " Net Pay: " << net_pay << endl;
                    data_name = data_record.substr(0,30);
                    prev = data_name;
                    total = 0;
                    
                }
               
                else if(prev.compare(data_name)==0)
                {
                    total += stod(data_hour);
                }
                
            }
        //close the file
        inputFile.close();
        }
}

int main()
{
    string filename;
       find_pay(filename); //call the void
   return 0;
}

这是我得到的输出，你看到 Bob Hu 不见了

Enter the filename: /Users/normatacuri/Desktop/employeehours.txt
Employee:Jimmy Bucket                  
Total Hours: 26 Gross Pay: $ 468 Tax 56.16 Net Pay: 411.84
Employee:John Doe                      
Total Hours: 32 Gross Pay: $ 576 Tax 69.12 Net Pay: 506.88
Employee:Ann Doe                       
Total Hours: 20 Gross Pay: $ 360 Tax 43.2 Net Pay: 316.8
Employee:Mary Jones                    
Total Hours: 16 Gross Pay: $ 288 Tax 34.56 Net Pay: 253.44
Program ended with exit code: 0

这是我正在使用的文件上的数据..

Jimmy Bucket                   8
Jimmy Bucket                   9
Jimmy Bucket                   10
Jimmy Bucket                   7
John Doe                       8
John Doe                       8
John Doe                       8
John Doe                       8
John Doe                       8
Ann Doe                        5
Ann Doe                        5
Ann Doe                        5
Ann Doe                        5
Ann Doe                        5
Mary Jones                     4
Mary Jones                     4
Mary Jones                     4
Mary Jones                     4
Mary Jones                     4
Bob Hu                         8
Bob Hu                         8
Bob Hu                         8
Bob Hu                         8
Bob Hu                         8

解决方法

我尝试将计算/显示代码放入 function() 并在您当前计算/显示数据的位置以及 while() 终止后调用它。但我认为我做错了。

你是对的，你一定做错了，但是你处理这种情况的方法也在 while() 终止之后很好。由于你没有展示这个尝试，我不能说你做错了什么。但我可以向您展示另一种方法，其中 EOF 情况也在循环内处理 - 对于 while 循环的这种替换，只需重新排列几条语句。

            for (; ; )
            {   bool f = (bool)getline(inputFile,data_record);
                if (!f || prev.compare(data_name = data_record.substr(0,30)) != 0)
                {   // do this on EOF as well as new name
                    //Calculate the gross pay,tax,net pay
                    float gross_pay = 18 * total;
                    float tax = (12 * gross_pay)/100;
                    float net_pay = gross_pay - tax;
                    if (total != 0)
                        cout << "Employee:" << prev << "\n"
                                "Total Hours: " << total << " Gross Pay: $ " << gross_pay
                             << " Tax " << tax << " Net Pay: " << net_pay << endl;
                    if (!f) break;
                    prev = data_name;
                    total = 0;
                }
                total += stod(data_hour = data_record.substr(31,2));
            }