如何解决试图在一组对象中找到最冷和最热的城市
// function
function findColdHot(array) {
// create an empty object
var resultObj = {};
// create coldest and hottest variables
let coldest = Infinity
let hottest = -Infinity
// iterate over the array
for (let i = 0; i < array.length; i++) {
if (array[i].temp > hottest) {
hottest = array[i].city;
} else if (array[i].temp < coldest) {
coldest = array[i].city;
}
}
// create coldest and hottest properties
resultObj['Coldest Place'] = coldest
resultObj['Hottest Place'] = hottest;
// return result object
return resultObj;
}
// tests
var input = [
{city: 'Helsinki',temp: 12},{city: 'Berlin',temp: 10},{city: 'oslo',temp: 4},{city: 'Nairobi',temp: 39},{city: 'Paris',temp: 6},{city: 'Istanbul',{city: 'Rome',temp: 25}
];
var actual = findColdHot(input);
var expected = {'Coldest Place': 'oslo','Hottest Place': 'Nairobi'};
console.log(actual)
我想弄清楚如何使用 for 循环并获取最冷和最热的城市。 我还尝试将最冷和最热的变量更改为:
let coldest = array.[0].temp
let hottest = array[0].temp
然后开始 for 循环 i = 1 但它仍然不起作用
我得到的不是预期的输出:
{ 'Coldest Place': 'Berlin','Hottest Place': 'Helsinki' }
或
{ 'Coldest Place': 'Berlin','Hottest Place': 'Nairobi' }
任何帮助将不胜感激!
解决方法
我对现有代码进行了一些更改,现在可以使用了
// function
function findColdHot(array) {
// create an empty object
var resultObj = {};
// create coldest and hottest variables
let coldest = array[0];
let hottest = array[0];
// iterate over the array
for (let i = 0; i < array.length; i++) {
if (array[i].temp > hottest.temp) {
hottest = array[i];
} else if (array[i].temp < coldest.temp) {
coldest = array[i];
}
}
// create coldest and hottest properties
resultObj['Coldest Place'] = coldest.city;
resultObj['Hottest Place'] = hottest.city;
// return result object
return resultObj;
}
// tests
var input = [
{city: 'Helsinki',temp: 12},{city: 'Berlin',temp: 10},{city: 'Oslo',temp: 4},{city: 'Nairobi',temp: 39},{city: 'Paris',temp: 6},{city: 'Istanbul',{city: 'Rome',temp: 25}
];
var actual = findColdHot(input);
var expected = {'Coldest Place': 'Oslo','Hottest Place': 'Nairobi'};
console.log(actual)
,
您将最冷和最热的城市定义为 Infinity
,我认为它可以解释为数字。然后将此数字与城市名称字符串值进行比较。
确保不要混合变量类型,尤其是在 JavaScript 中。
function findColdHot(array) {
// create an empty object
var resultObj = {};
// create coldest and hottest variables
let coldest = array[0];
let hottest = array[0];
// iterate over the array
for (let i = 0; i < array.length; i++) {
if (array[i].temp > hottest.temp) {
hottest = array[i];
} else if (array[i].temp < coldest.temp) {
coldest = array[i];
}
}
// create coldest and hottest properties
resultObj['Coldest Place'] = coldest.city
resultObj['Hottest Place'] = hottest.city;
// return result object
return resultObj;
}
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