如何解决从 Json 文件中获取子节点数据
我从 JSON 文件中获得了一个列表,但如何使用 Python 从每个结果中获取用户名和结果?
Json 文件
{
"Users" : {
"abcde" : {
"email" : "123@gmail.com","gender" : "Male","password" : "123","result" : "Back Road Explorer","username" : "abcde"
},"halo" : {
"email" : "halo@gmail.com","password" : "halo","result" : "Outdoor Adventure","username" : "halo"
},"01" : {
"email" : "01@gmail.com","password" : "dajcaq","result" : "Culinary Connoisseur","username" : "01"
}
}
结果应该是:
username = abcde,halo,01
result = Back Road Explorer,Outdoor Adventure,Culinary Connoisseur
解决方法
json = {...}
result_username = []
result = []
for username in json['Users']:
result_username += [username]
result += [json['Users'][username]['result']]
print ('username : ',','.join(result_username))
print ('result : ','.join(result))
结果
username : abcde,halo,01
result : Back Road Explorer,Outdoor Adventure,Culinary Connoisseur
,
可能你需要这样的东西:
js = {
"Users": {
"abcde": {
"email": "123@gmail.com","gender": "Male","password": "123","result": "Back Road Explorer","username": "abcde"
},"halo": {
"email": "halo@gmail.com","password": "halo","result": "Outdoor Adventure","username": "halo"
},"01": {
"email": "01@gmail.com","password": "dajcaq","result": "Culinary Connoisseur","username": "01"
}
}
}
def parse_json(js):
usernames,results = [],[]
for value in js['Users'].values():
usernames.append(value["username"])
results.append(value["result"])
usernames,results = ','.join(usernames),'.join(results),print(f'username = {usernames}')
print(f'result = {results}')
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