VBA excel .Left .Top 当图片旋转时

如何解决VBA excel .Left .Top 当图片旋转时

我尝试了无数次，但仍然有这个问题。我尝试使用 excel 中的宏将图片放入给定范围内。只要图片不旋转（方向 = 0）就没有问题。但是从图片旋转的那一刻起，一切都会流血。我已经发现图片的高度和宽度也旋转了。但是 .top 和 .left 会发生什么？这是我的代码：

Function fotoInsert(ByVal PictureFileName As String,ByVal rng As Range)

    Set pic = ActiveSheet.Pictures.Insert(PictureFileName)
    
    If pic.ShapeRange.Rotation = 90 Then
        With pic
              'keep original aspect ratio
              .ShapeRange.LockAspectRatio = msoTrue
              
              'Picture's aspect is less than rng aspect then adjust the picture's width to fit rng
             If (pic.Width \ pic.Height) <= (rng.Height \ rng.Width) Then
                 .Width = rng.Height - 1 'pictures' width is the larger height,by this line it fits exactly into range width
                 .Left = rng.Left + ((rng.Width - pic.Height) / 2)
                 .Top = rng.Top + 1
             Else 'Picture's aspect is greater than rng aspect then adjust the picture's height to fit rng
                 .Width = rng.Height - 1 'picture's heigth is larger than its width,this line makes it exactly fit int range height
                 .Top = rng.Top
                 .Left = rng.Left
             End If
        .Placement = xlMoveAndSize
        .PrintObject = True
        End With
    Else
        With pic
         'keep original aspect ratio
         .ShapeRange.LockAspectRatio = msoTrue
         
         'Picture's aspect is less than rng aspect then adjust the picture's width to fit rng
            If (.Height \ .Width) <= (rng.Height \ rng.Width) Then
                
                .Width = rng.Width - 1 'pictures' width is the larger height,by this line it fits exactly into range width
                .Left = rng.Left + 1 'position at left range border
                .Top = rng.Top + ((rng.Height - pic.Height) / 2) 'position in center of range height
            Else 'Picture's aspect is greater than rng aspect then adjust the picture's height to fit rng
                .Top = rng.Top + 1 'position at upper border of the range[/color]
                .Height = rng.Height - 1 'picture's heigth is larger than its width,this line makes it exactly fit int range height
                .Left = rng.Left + ((rng.Width - pic.Width) / 2) 'position in center of range width
            End If
        .Placement = xlMoveAndSize
        .PrintObject = True 'make sure picture gets printed
        End With
    End If
End Function

所以问题出现在第一个 If 条件（旋转 = 90） 在其他情况下，我似乎没有问题。

我用来测试的典型范围是：

"A7:N46"

解决方法

感谢您的快速回复！

我试图做的是在预先确定的范围内拟合任何给定的图片。所以是的，我也会收到旋转的图片。

这个想法是用户选择图片（最多 4 张）并自动排列和调整它们的大小以适应一张预先确定的 Excel 工作表。所以我制作了 4 个场景（不同的范围）如何在一张纸上排列这些图片。这是通过 switch case 在其他例程中完成的。

到目前为止，此代码适用于未旋转的图片。从那里旋转的那一刻起，它就变得凌乱不堪，图片“流血”。如果有其他方法可以解决我的问题，我很高兴在这里提供。