生成多个列表和绘图的 while 循环会产生内存错误

如何解决生成多个列表和绘图的 while 循环会产生内存错误

我有以下代码，我想在散点图中根据迭代次数或太阳能输入绘制温度。

我不断收到内存错误，我认为这是由于此代码创建的列表的大小造成的。有什么方法可以将输出存储在其他地方或分解此循环，使输出不会那么大？我目前使用的是 python 3 64 位。

import numpy as np
import matplotlib.pyplot as plt

#define constants


LRange = [1290,1310] #W/m2
Episilon = 1 #no units
Sigma = 5.67E-08 #Wm-2K-4

#L,albedo,nIters = input("").split()
#L,nIters = [float(L),float(albedo),int(nIters) ]

L = 1250
albedo = 0.15
nIters = 1

Ice_Lat_m = 1.5
Ice_lat_c = -322.5
Alb_m = -0.01
Alb_c = 2.8

plottype = "iterDown" #"L","iterUp","iterDown"

x = []
y = []

while L < LRange[1]+1:
    for iter in range(nIters):
        T = L * ( 1- albedo) / 4 * Sigma
        T = T ** (0.25)
        albedo = Alb_m * T +Alb_c
        albedo = min(albedo,0.65)
        albedo = max(albedo,0.15)
        lat_ice = Ice_Lat_m * T + Ice_lat_c
        lat_ice = min(lat_ice,90)
        lat_ice = max(lat_ice,0)
       # if plottype is "iter" or plottype is "iterup":
            #x.append(iter)
           # y.append(T)
   # if plottype is "iter" or plottype is "iterup":
       # x.append(np.nan)
        #y.append(np.nan)
  #  if plottype is "L":
       # x.append(L)
       # x.append(T)
    L = L + 10

while L > LRange[0]-1:
    for iter in range(nIters):
        T = L * ( 1- albedo) / 4 * Sigma
        T = T ** (0.25)
        albedo = Alb_m * T +Alb_c
        albedo = min(albedo,0)
        #if plottype is "iter" or plottype is "iterdown":
            #x.append(iter)
            #y.append(T)
   # if plottype is "iter" or plottype is "iterdown":
       # x.append(np.nan)
        y.append(np.nan)
    #if plottype is "L":
        #x.append(L)
        #x.append(T)
    L = L + 10

plt.plot(x,y)
plt.show()

print(T,albedo)