如何解决在opengl中将金字塔更改为四面体
首先,我对 openGL 很陌生,所以我还不知道所有“基本”的东西。我在一本书中做这个练习,我已经能够画一个金字塔,但我现在想画一个四面体。但我似乎无法理解它。我总是以奇怪或不完整的形状结束。如果我还没有做任何其他事情,请告诉我。 这是代码。任何帮助表示赞赏。
float pt1 = 1.0f;
float pt2 = 0.0f;
glBegin(GL_TRIANGLES);
// Front
glColor3f(1.0f,0.0f,0.0f); // Red
glVertex3f(pt2,pt1,pt2);
glVertex3f(-pt1,-pt1,pt1);
glVertex3f(pt1,pt1);
// Right
glColor3f(0.0f,1.0f); // Blue
glVertex3f(pt2,pt2);
glVertex3f(pt1,-pt1);
// Back
glColor3f(0.0f,1.0f,0.0f); // Green
glVertex3f(pt2,-pt1);
glVertex3f(-pt1,-pt1);
// Left
glColor3f(1.0f,0.0f); // Yellow
glVertex3f(pt2,pt1);
glEnd();
解决方法
Tetrahedron 由 4 个顶点组成:
const float s_8_9 = sqrt(0.8f / 0.9f); // = 0.9428f
const float s_2_9 = sqrt(0.2f / 0.9f); // = 0.4714f
const float s_2_3 = sqrt(0.2f / 0.3f); // = 0.8165f
float vertices[4][3] = {
{ 0.0f,0.0f,1.0f },{ s_8_9,-1.0f / 3.0f},{-s_2_9,s_2_3,-s_2_3,};
顶点形成 4 个三角形面:
int indices[4][3] = {{0,2,1},{0,3,2},{1,0},3}};
使用 vertices
和 indices
绘制四面体:
glBegin(GL_TRIANGLES);
// Front
glColor3f(1.0f,0.0f); // Red
for (int i = 0; i < 3; i++)
glVertex3fv(vertices[indices[0][i]]);
// Right
glColor3f(0.0f,1.0f); // Blue
for (int i = 0; i < 3; i++)
glVertex3fv(vertices[indices[1][i]]);
// Back
glColor3f(0.0f,1.0f,0.0f); // Green
for (int i = 0; i < 3; i++)
glVertex3fv(vertices[indices[2][i]]);
// Left
glColor3f(1.0f,0.0f); // Yellow
for (int i = 0; i < 3; i++)
glVertex3fv(vertices[indices[3][i]]);
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。