二进制人类可读到实际大小

如何解决二进制人类可读到实际大小

我想将人类可读的大小（例如“10Mi”）转换回实数大小

我写了以下内容，但我似乎在转换中遗漏了一些东西

function humanFileSizetoSize (sizeString) {
    const units = ['Ki','Mi','Gi','Ti','Pi','Ei','Zi','Yi'];
    const unitString = units.find(unit => sizeString.includes(unit));
    const power = units.indexOf(unitString) + 1;
    const size = parseFloat(sizeString.slice(0,sizeString.indexOf(unitString)))
    return parseInt(size * (1024**power));
}

console.log(humanFileSizetoSize("10Mi"))
console.log(humanFileSizetoSize("1.5Mi"))

解决方法

假设 1 MiB 等于 1048576 字节，似乎可以按预期工作。

虽然可以缩短，并且无需库即可完成

const units = [,'Ki','Mi','Gi','Ti','Pi','Ei','Zi','Yi'];
const re = /(\d+(?:\.\d+)?)([KMGTPEZYi]{2})/g;
const humanFileSizeToSize = sizeString => {
  const [[_,size,unit]] = sizeString.matchAll(re);
  const power = units.indexOf(unit)
  return parseInt(size * (1024 ** power));
}

console.log(humanFileSizeToSize("1Ki"))
console.log(humanFileSizeToSize("1Mi"))
console.log(humanFileSizeToSize("1.5Mi"))
console.log(humanFileSizeToSize("10Mi"))
console.log(humanFileSizeToSize("1Gi"))