从字典中获取数据的更简单方法

如何解决从字典中获取数据的更简单方法

我有一本字典： 元组的最后一个条目是射门时间。 例如：巴西球员奥斯卡第90分钟射门

players = {
    "Brazil": [
        (12,"Júlio César","Goalkeeper",[]),(4,"David Luiz","Defender",(6,"marcelo",(13,"dante",(23,"Maicon",(5,"Fernandinho","Midfielder",(7,"Hulk",(8,"Paulinho",(11,"Oscar",[90]),(16,"Ramires",(17,"Luiz Gustavo",(19,"Willian",(9,"Fred","Striker",],"Germany": [
        (1,"Manuel Neuer","Benedikt Höwedes","Mats Hummels","Philipp Lahm","Per Mertesacker",(20,"Jérôme Boateng","Sami Khedira",[29]),"Bastian Schweinsteiger","Mesut Özil","Thomas Müller",[11]),(14,"Julian Draxler",(18,"Toni Kroos",[24,26]),"André Schürrle",[69,79]),"Miroslav Klose",[23]),}

我想创建一个函数，将球队和一分钟作为输入，并返回到该分钟的射门数。 我是这样试的：

def score_at_minute(team,minute):
    global players
    goals = [goals for (number,player,position,goals) in players[team] if len(goals)>=1]
    goals_1 = [goal[0] for goal in goals if len(goal)>=1 if goal[0] <= minute]
    goals_2 = [goal[1] for goal in goals if len(goal) ==2 if goal[1]<= minute]
    all_goals = goals_1+goals_2
    return len(all_goals)

我的函数调用如下所示：

score_at_minute("Germany",90)

是否有更简单的方法或最好的单衬方式？

解决方法

你可以简单地使用列表理解

# For Germany
# For less than 90 minutes
len([eg for _,_,g in players['Germany'] for eg in g if eg<90])

7

,

这个怎么样 -

def score_at_minute(x,y):
    return len([j for i in players.get(x) for j in i[3] if j<=y])

score_at_minute("Germany",25)

3

另一个版本 -

score_at_minute = lambda x,y: len([j for i in players.get(x) for j in i[3] if j<=y])

score_at_minute('Germany',90)

7

---

这是如何工作的 -

1. players.get(x) 获取国家 x 下的球员和目标列表
2. i[3] 是包含目标列表的项目
3. 迭代时，您将得到一个列表列表，其中每个子列表都包含目标。 [[],[],[24],[32,45]] .. 等
4. 您现在可以使用 [item for sublist in list for item in sublist]
来展平列表列表
5. 然后您可以对这个列表应用过滤器（小于等于输入分钟）
6. 最后计算长度。

,

使用items()

def score_at_minute(team,minute):        
    for key,val in players.items():
        if key==team:            
            return(len([j for i in val  for j in i[3] if j <=minute]))