(Pygame) 这个函数有什么问题？

如何解决(Pygame) 这个函数有什么问题？

所以，我一直在研究用 Pygame 制作的蛇游戏。到目前为止，一切都很好，除了一个问题：当蛇吃水果时，有时会出现在蛇体内的水果（随机产卵）。所以，为了避免这种情况，我做了这个功能：

def random_fruit(body_pos):
    global general_fruit_x,general_fruit_y  # Fruit rectangle coordinates
    while True:
        general_fruit_x = randrange(window[0] // snake.w) * snake.w  # (Snake is a pygame.Rect)
        general_fruit_y = randrange(window[1] // snake.h) * snake.h
        if len(list(filter(lambda z: body_pos == (general_fruit_x,general_fruit_y),body_pos))) > 0:
            continue  # If the spawning position of the fruit is the same as the snake's body,we continue the loop
        else:
            break  # If not,we are done
    set_obj_coordinates(general_fruit,general_fruit_x,general_fruit_y)  # set fruit random position

并在主游戏循环中实现：

if fruit_eated:
    random_ind1 = random_ind2
    snake_len += 1
    apple_sound.play()
    random_fruit(snake_pos)  # snake_pos is a list of tuples with all snake's body coordinates
    for m in range(3):
        snake_imgs[random_ind1][m] = img("snake_" + snake_colors[random_ind1] + str(m + 1))  # Reset snake image
    random_ind2 = randint(0,3)
    if x_move < 0:
        rotate_imgs(90,random_ind1)
    if x_move > 0:
        rotate_imgs(-90,random_ind1)
    if y_move > 0:
        rotate_imgs(180,random_ind1)
    if y_move < 0:
        pass

但似乎 random_fruit 函数忽略了蛇身体的状况。

完整代码如下：https://github.com/n4tm/PySnake/tree/main/snake

解决方法

您必须检查身体的 any 位置是否等于水果的新随机位置：

if len(list(filter(lambda z: body_pos == (general_fruit_x,general_fruit_y),body_pos))) > 0:`

if any(pos == (general_fruit_x,general_fruit_y) for pos in body_pos):

random_fruit 函数：

def random_fruit(body_pos):
    global general_fruit_x,general_fruit_y
    while True:
        general_fruit_x = randrange(window[0] // snake.w) * snake.w 
        general_fruit_y = randrange(window[1] // snake.h) * snake.h
        if not any(pos == (general_fruit_x,general_fruit_y) for pos in body_pos):
            break
    set_obj_coordinates(general_fruit,general_fruit_x,general_fruit_y)