如何解决将 Bazel 规则输出的目录扩展为另一个规则的平面输出
我正在尝试打包要上传到 Google Cloud 的包。我有一个来自我所做的角度构建的 pkg_web
输出,如果我传递给我正在生成的这个自定义规则,它是一个 File
对象,它是文件的目录。我生成的自定义规则采用 app.yaml 等,以及包和上传。
但是,bundle 变成了一个目录,我需要在命令的根目录中扩展该目录的文件才能上传。
例如:
- bundle/index.html <-- bundle directory
- bundle/main.js
- app.yaml
我需要:
- index.html
- main.js
- app.yaml
我的规则:
deploy(
name = "deploy",srcs = [":bundle"] <-- pkg_web rule,yaml = ":app.yaml"
)
规则实施:
def _deploy_pkg(ctx):
inputs = []
inputs.append(ctx.file.yaml)
inputs.extend(ctx.files.srcs)
script_template = """
#!/bin/bash
gcloud app deploy {yaml_path}
"""
script = ctx.actions.declare_file("%s-deploy" % ctx.label.name)
ctx.actions.write(script,script_content,is_executable = True)
runfiles = ctx.runfiles(files = inputs,transitive_files = depset(ctx.files.srcs))
return [DefaultInfo(executable = script,runfiles = runfiles)]
谢谢你的想法!
解决方法
似乎有点过分,但我最终使用自定义 shell 命令来完成此操作:
def _deploy_pkg(ctx):
inputs = []
out = ctx.actions.declare_directory("out")
yaml_out = ctx.actions.declare_file(ctx.file.yaml.basename)
inputs.append(out)
ctx.actions.run_shell(
outputs = [yaml_out],inputs = [ctx.file.yaml],arguments = [ctx.file.yaml.path,yaml_out.path],progress_message = "Copying yaml to output directory.",command = "cp $1 $2",)
for f in ctx.files.srcs:
if f.is_directory:
ctx.actions.run_shell(
outputs = [out],inputs = [f],arguments = [f.path,out.path],progress_message = "Copying %s to output directory.".format(f.basename),command = "cp -a -R $1/* $2",)
else:
out_file = ctx.actions.declare_file(f.basename)
inputs.append(out_file)
ctx.actions.run_shell(
outputs = [out_file],out_file.path],# This is what we're all about here. Just a simple 'cp' command.
# Copy the input to CWD/f.basename,where CWD is the package where
# the copy_filegroups_to_this_package rule is invoked.
# (To be clear,the files aren't copied right to where your BUILD
# file sits in source control. They are copied to the 'shadow tree'
# parallel location under `bazel info bazel-bin`)
command = "cp -a $1 $2",)
....
``
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