如何解决API Google JSON 到 C
我对我的 c 代码有疑问,
我的代码在做什么?
- 调用 Google Api“方向”
- 获取一个包含json结构的大字符串“s”
- 将我的字符串 s 写入文件
我的问题是什么? 我想创建一个自动结构,因为我的结构总是不同的。例如有时如果只有 200 或 1000 坐标..
#include <stdio.h>
#include <curl/curl.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>
#define MAX 300
struct string {
char *ptr;
size_t len;
};
void init_string(struct string *s) {
s->len = 0;
s->ptr = malloc(s->len+1);
if (s->ptr == NULL) {
fprintf(stderr,"malloc() Failed\n");
}
s->ptr[0] = '\0';
}
size_t writefunc(void *ptr,size_t size,size_t nmemb,struct string *s)
{
size_t new_len = s->len + size*nmemb;
s->ptr = realloc(s->ptr,new_len+1);
if (s->ptr == NULL) {
fprintf(stderr,"realloc() Failed\n");
}
memcpy(s->ptr+s->len,ptr,size*nmemb);
s->ptr[new_len] = '\0';
s->len = new_len;
return size*nmemb;
}
void getRoad(double doubleLatitude,double doubleLongitude,char *villeDestination[MAX]){
printf("Function : getRoad\n");
printf("parameters latitude -%f-\n",doubleLatitude);
printf("parameters longitude -%f-\n",doubleLongitude);
printf("parameters villeDestination -%s-\n",villeDestination);
char URL_BASE[MAX],URL;
// CONVERT DOUBLE TO STRING
char stringLatitude[50];
char stringLongitude[50];
snprintf(stringLatitude,50,"%f",doubleLatitude);
snprintf(stringLongitude,doubleLongitude);
// WE ARE BUILDING URL URL
strcpy (URL_BASE,"https://maps.googleapis.com/maps/api/directions/json?origin=");
strcat(URL_BASE,stringLatitude);
strcat(URL_BASE,",");
strcat(URL_BASE,stringLongitude);
strcat(URL_BASE,"&destination=");
strcat(URL_BASE,villeDestination);
strcat(URL_BASE,"&avoid=highways&mode=bicycling&key=AIzaSyBpj0XoMAHi8naH5k-S8mAr0nexwCQvv2g");
// OUR URL,YOU CAN TEST IT IN FIREFOX !
printf("%s\n",URL_BASE);
CURL *curl;
CURLcode res;
curl_global_init(CURL_GLOBAL_DEFAULT);
curl = curl_easy_init();
if(curl) {
struct string s;
init_string(&s);
curl_easy_setopt(curl,CURLOPT_URL,URL_BASE);
#ifdef SKIP_PEER_VERIFICATION
curl_easy_setopt(curl,CURLOPT_SSL_VERIFYPEER,0L);
#endif
#ifdef SKIP_HOSTNAME_VERIFICATION
curl_easy_setopt(curl,CURLOPT_SSL_VERIFYHOST,0L);
#endif
curl_easy_setopt(curl,CURLOPT_WRITEFUNCTION,writefunc);
curl_easy_setopt(curl,CURLOPT_WRITEDATA,&s);
res = curl_easy_perform(curl);
printf("%s\n",s.ptr);//DEBUG
// OPEN A FILE AND WRITE DATA
FILE *fptr;
fptr = fopen("dataJson.json","w");
if (fptr == NULL) {
printf("Error!");
exit(1);
}
fprintf(fptr,"%s",s.ptr);
fclose(fptr);
//printf("%s\n",curl_easy_perform(curl));//DEBUG
if(res != CURLE_OK)
fprintf(stderr,"curl_easy_perform() Failed: %s\n",curl_easy_strerror(res));
curl_easy_cleanup(curl);
}
curl_global_cleanup();
}
/*
* Exemple type adepart avec des coordonnées
*
* origin 50.642782,2.833267
* destination paris
*
* https://maps.googleapis.com/maps/api/directions/json?origin=50.642782,2.833267&destination=paris&avoid=highways&mode=bicycling&key=AIzaSyBpj0XoMAHi8naH5k-S8mAr0nexwCQvv2g
*/
int main(void){
//getCoordinate();
// Coord depart - ville destination
getRoad(50.642782,2.833267,"nieppe");
return 0;
}
解决方法
我不知道如何像这样访问大字符串中的数据 { "geocoded_waypoints" : [ { "geocoder_status" : "OK","place_id" : "ChIJbRcWwsZMFkcRcXvXdyuxSyw","types" : [ "street_address" ] },{ "geocoder_status" : "OK","place_id" : "ChIJD7fiBh9u5kcRYJSMaMOCCwQ","types" : [ "locality","political" ] } ],"routes" : [ { "bounds" : { "northeast" : { "lat" : 52.2236303,"lng" : 20.203097 }
您似乎想要一个 JSON 实现来解析 JSON 格式的字符串。也许你的系统上已经有了 JSON-C;在这种情况下,您只需将您的程序与 -ljson-c
相关联,例如您可以使用以下调用:
#include <json-c/json.h>
...
struct json_object *obj = json_tokener_parse(s.ptr);
if (!obj) { fputs("json_tokener_parse failed\n",stderr); return; }
struct json_object *way = json_object_object_get(obj,"geocoded_waypoints");
if (!way) { fputs("no geocoded_waypoints\n",stderr); return; }
size_t len = json_object_array_length(way);
printf("There are %zd waypoints.\n",len);
for (size_t idx = 0; idx < len; ++idx)
{ printf("waypoint %zd:\n",idx);
struct json_object *point = json_object_array_get_idx(way,idx);
printf("geocoder_status is %s\n",json_object_get_string(json_object_object_get(point,"geocoder_status")));
printf("place_id is %s\n","place_id")));
printf("types is %s\n","types")));
}
struct json_object *routes = json_object_object_get(obj,"routes");
if (!routes) { fputs("no routes\n",stderr); return; }
size_t routeslen = json_object_array_length(routes);
printf("There are %zd routes.\n",routeslen);
for (size_t idx = 0; idx < routeslen; ++idx)
{ printf("route %zd:\n",idx);
struct json_object *route = json_object_array_get_idx(routes,idx);
printf("bounds is %s\n",json_object_get_string(json_object_object_get(route,"bounds")));
}
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