使用字典键删除链表中的节点

如何解决使用字典键删除链表中的节点

我有以下方法，我想从列表中删除 {5285831021: 'Hayes'}。我只通过 5285831021 怎么办？

class Node:
    def __init__(self,data=None):
        self.data = data
        self.prev = None
        self.next = None

class DoublyLinkedList:
    def __init__(self):
        self.head = None
        self.tail = None

    def insert(self,pair):
        if not isinstance(pair,Node):
            pair = Node(pair)
        if self.is_empty():
            self.head = pair
        else:
            current = self.head
            while current.next:
                current = current.next
            current.next = pair
            pair.prev = current
        self.tail = pair

    def __str__(self):
        to_print = ''
        current = self.head
        while current:
            to_print += f'{current.data}<->'
            current = current.next
        if to_print:
            return f'[{to_print[:-3]}]'
        return '[]'

这是我创建的通过给定键删除节点的方法。

    def delete(self,key):
        pass

my_list = DoublyLinkedList()
my_list.insert({2363688062: 'Clark'})
my_list.insert({5598260087: 'Russell'})
my_list.insert({5285831021: 'Hayes'})
my_list.insert({5285234321: 'Henderson'})
my_list.insert({9447143408: 'Hamilton'})

my_list.delete(5285831021)
print(my_list)

解决方法

def delete(self,value):
    curr = self.head
    while curr:
        if list(curr.data.keys())[0] == value:
            node_to_delete = curr.next
            curr.data = node_to_delete.data
            curr.next = node_to_delete.next
            return
        curr = curr.next