获取 tkinter 中 Toplevel 窗口的数量

如何解决获取 tkinter 中 Toplevel 窗口的数量

有没有办法在 tkinter 中获取顶层窗口的数量？

代码如下：

from tkinter import *

root = Tk()
root.geometry("500x500")

def get_number_of_toplevel_windows():
    # Code to count the number of toplevel windows
    pass

toplevel_1 = Toplevel(root)
toplevel_2 = Toplevel(root)
toplevel_3 = Toplevel(root)

get_button = Button(root,text = "Get number of toplevel windows",command = get_number_of_toplevel_windows)
get_button.pack()

mainloop()

在这里，当我点击 get_button 时，我想打印顶级窗口的数量（在本例中为三个。

有没有办法在 tkinter 中实现这一点？

如果有人能帮助我就好了。

解决方法

您可以只使用 winfo_children() 来调出所有子项，然后检查其中的 'toplevel'，例如：

def get_number_of_toplevel_windows():
    tops = [] # Empty list for appending each toplevel
    for widget in root.winfo_children(): # Looping through widgets in main window
        if '!toplevel' in str(widget): # If toplevel exists in the item
            tops.append(widget) # Append it to the list
             
    print(len(tops)) # Get the number of items in the list,AKA total toplevels

这也不需要任何外部模块。

或者：

def get_number_of_toplevel_windows():
    tops = []
    for widget in root.winfo_children(): # Loop through each widget in main window
        if isinstance(widget,Toplevel): # If widget is an instance of toplevel
            tops.append(widget) # Append to a list
             
    print(len(tops)) # Get the number of items in the list,AKA number of toplevels

后一种方法似乎更有效，因为它检查项目的实例，并且不像第一种方法那样比较字符串。

,

此解决方案仅适用于 Windows 平台（需要 pywinauto 库）：

import tkinter as tk
from pywinauto import Desktop

NAME = 'Program name'

def get_number_of_toplevel_windows():
    windows = Desktop(backend='uia').windows()
    print(len([w.window_text() for w in windows if w.window_text() == NAME])-1)

root = tk.Tk()
root.title(NAME)
tk.Toplevel(root)
tk.Toplevel(root)
tk.Toplevel(root)
tk.Button(root,text='Get number of toplevel windows',command=get_number_of_toplevel_windows).pack()
tk.mainloop()

输出：

3

,

这对我有用

from tkinter import *

root = Tk()
root.geometry("500x500")    
toplevel_1 = Toplevel(root)

count = 0 #Total count of Toplevels
def get_number_of_toplevel_windows(ventana):
    global count
    for a,b in ventana.children.items(): #Getting list of root window's children and using recursion 
        if isinstance(b,Toplevel):
            count+=1 #If toplevel then count += 1
        get_number_of_toplevel_windows(b)

def printresult():
    print(count)
get_button = Button(root,text = "Get number of toplevel windows",command = printresult)
get_button.pack()
get_number_of_toplevel_windows(root)
root.mainloop()