PHP 反转基值逻辑 + ? = 结果值

如何解决PHP 反转基值逻辑 + ? = 结果值

我有一个基值和结果最终更改的值我如何反向计算以获得更改的除法？
目标是当我输入结果值时，它应该解释使用什么变量进行计算，就像 A+?=C

<?PHP
/*this is an behind logic changes example*/
//possible value -2 to 5
$atk    = 0;
$matk   = 1;
$def    = 0;
$aspd   = 0;
$hit    = 0;
$crit   = 0;
$eva    = 0;
$move   = 5;
$hp     = 0;
$ap     = 0;

/*default magic number of base value*/
$base = array(
        "atk"       => 1,"matk"      => 8,"def"       => 64,"aspd"      => 512,"hit"       => 4096,"crit"      => 32768,"eva"       => 262144,"move"      => 2097152,"hp"        => 16777216,"ap"        => 134217728,);

/*logic method to calculate base value*/
$base_sum=0;
foreach ($base as $key => $val) {
    echo "\n".$key." -> ".$val;
    $base_sum+=$val;
}
echo "\n"."Total -> ".$base_sum;
/*the real base value sum is double of base value*/
$final_base = $base_sum * 2;
echo "\n=================================";
echo "\n"."Base -> ".$final_base;
echo "\n=================================";

/*generated sample changes value*/
$changes = array(
    "atk"       => $atk,"matk"      => $matk,"def"       => $def,"aspd"      => $aspd,"hit"       => $hit,"crit"      => $crit,"eva"       => $eva,"move"      => $move,"hp"        => $hp,"ap"        => $ap
);


/*logic to apply changes in base value sum*/
$change_num = 0;
foreach ($changes as $key => $val) {
    $change_num = $change_num + ($val*$base[$key]);
    echo "\n".$key." -> ".$val."*".$base[$key]." = ".$val*$base[$key];
}
echo "\n"."Changes -> ".$change_num;
echo "\n"."=================================";
$final_change = $final_base + $change_num;
echo "\n"."Final change - > ".$final_change."\n";

?>

输出：

atk -> 1
matk -> 8
def -> 64
aspd -> 512
hit -> 4096
crit -> 32768
eva -> 262144
move -> 2097152
hp -> 16777216
ap -> 134217728
Total -> 153391689
=================================
Base -> 306783378
=================================
atk -> 0*1 = 0
matk -> 1*8 = 8
def -> 0*64 = 0
aspd -> 0*512 = 0
hit -> 0*4096 = 0
crit -> 0*32768 = 0
eva -> 0*262144 = 0
move -> 5*2097152 = 10485760
hp -> 0*16777216 = 0
ap -> 0*134217728 = 0
Changes -> 10485768
=================================
Final change - > 317269146

当我给出输入时的预期结果 317269146 返回应该是 matk = 1,move = 5

任何人都可以分享任何想法吗？谢谢！

解决方法

我终于找到了灵感来自@El_Vanja 的答案，他/她提到了一些逻辑规则，我尝试实现逻辑然后它起作用

/*reversing the result value back to steps*/
echo "\n"."Reversing value of changes 317269146";
/*find diff = final_change - final_base*/
$change_num = 317269146-306783378;

    $ap_  = intval($change_num / 134217728);
    $ap   = $change_num % 134217728;
    
    $hp_  = intval($ap / 16777216);
    $hp   = $change_num % 16777216;

    $move_  = intval($hp / 2097152);
    $move = $change_num % 2097152;

    $eva_  = intval($move_ / 262144);
    $eva  = $change_num % 262144;

    $crit_  = intval($eva / 32768);
    $crit = $change_num % 32768;
    
    $hit_  = intval($crit / 4096);
    $hit  = $change_num % 4096;
    
    $aspd_ = intval($hit / 512);
    $aspd = $change_num % 512;

    $def_ = intval($aspd / 64);
    $def  = $change_num % 64;

    $matk_ = intval($def / 8);
    $matk = $change_num % 8;

    $atk_ = intval($matk / 1);
    $atk  = $change_num % 1;
       
    echo 
    "\n\n"."atk  -> ".$atk_ .
    "\n"."matk -> ".$matk_.
    "\n"."def  -> ".$def_.
    "\n"."aspd -> ".$aspd_.
    "\n"."hit  -> ".$hit_.
    "\n"."crit -> ".$crit_.
    "\n"."eva  -> ".$eva_.
    "\n"."move -> ".$move_.
    "\n"."hp   -> ".$hp_.
    "\n"."ap   -> ".$ap_;

输出

Reversing value of changes 317269146

atk  -> 0
matk -> 1
def  -> 0
aspd -> 0
hit  -> 0
crit -> 0
eva  -> 0
move -> 5
hp   -> 0
ap   -> 0

幻数在计算中起着重要作用 谢谢！